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Sergeeva-Olga [200]
3 years ago
7

Decide whether the function is linear. Then evaluate the function for the given value of x. 43-48 pls 20 points

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

3.14-(7543)+23

Step-by-step explanation:

I hope that answerd your question have a nice day!

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find the area of a circle that has a diameter of 11inches approximate as 13.4 round your answer to the hundreth
Vinil7 [7]

To find the area of a circle you do pi (3.14) multiplied by the radius squared.

The radius is half of the diameter: 11 / 2 = 5.5in

The radius squared is 5.5^2 = 30.25

Then take the squared radius and multiply that by pi 30.25 * 3.14 = 94.985

So the area of the circle is about 94. 99 in.

Hope this helped! Mark as Brainliest please! :)))

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3 years ago
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Is the function g(x)=9<br> x+1 linear or nonlinear?
Licemer1 [7]
It is a linear function
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4 years ago
of the 150 people surveyed seven out of 10 said they owned at least one pet how many of the people surveyed owned pets
suter [353]
15 times 7, which is 105.
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3 years ago
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What is the form of the Pythagorean triple generator?​
stepladder [879]

Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

Step-by-step explanation:

We can rewrite left side into right side form

(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

we can expand it

(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4

(x^2+y^2)^2=x^4+y^4+2x^2y^2

we can add and subtract 2x^2y^2

(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

4 0
3 years ago
Read 2 more answers
Multiply and simplify. (x - 1)(x - 1)(x - 1)
Tanzania [10]
(sorry if it's too late and you've already figured it out, but here you go anyway)
The easiest way to do this is to start by FOILing then add.
So just start with (x-1)(x-1)
(x-1)(x-1)
Front: (x*x) = x^2
Outer: (x*-1) = -x
inner: (-1*x) = -x
Last: (-1*-1) = 1
Added: x^2 -2x +1
Now take that answer and do the same thing with (x-1). It's basically the same thing, just with an added thing you need to multiply.
(x-1)(x^2-2x+1)
(x*x^2) = x^3
(x*2x) = 2x^2
(x*1) = x
(-1*x^2) = -x^2
(-1*-2x) = 2x
(-1*1) = -1
Now add everything together:
x^3+2x^2+x-x^2+2x-1
The answer is:
x^3+x^2+3x-1
3 0
3 years ago
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