1. As x approaches 1, f(x) approaches 3-1, that is 2.
If a = 2 and b = 3, f(1) = 2(1)^2 + 3(1) = 5
So there is a 'jump' in values of x at x = 1. So its not continuous at x=1.
2. For continuity at x = 1, ax^2 + bx must = 2 that is when a + b = 2.
3. for continuity at x = 2 , ax^2 + bx must be = 0 that is when a*2^2 + 2b = 0
- that is 4a + 2b = 0.
4. we have system of equations:-
a + b = 2
4a + 2b = 0
this gives a = -2 and b = 4 So f(x) is continuous when a = -2 and b = 4.
Answer:
(-8.64) / (-0.024) = 360
Step-by-step explanation:
You have to type like this in your question;
(-8.64) / (-0.024)
or 
.
Bye!
24.3
bcoz to round to tenths place need to chk with hundreths place.
As 1 is in hudredths place so the digit in tenths place remains the same
Answer:
of the cake
Step-by-step explanation:
add 
and 
to see the total amount of cake eaten.
a. find the common denominator: 8 x 3 = 24 and 6 x 4 = 24
b. multiply accordingly to get the correct numerator: 
+ 
c. add: + = 
subtract found value from total to find left over cake.
a. 24 - 7 = 14
simplify.
a. 
=
You are left with of the cake.
