Answer:
The molar concentration of the final solution is 1.71
Explanation:
Molarity is a way of expressing the concentration of solutions and indicates the number of moles of solute dissolved per liter of solution.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution.:
Molarity is expressed in units ().
Then, the number of moles of solute can be calculated as:
number of moles of solute= molarity* volume
So, in this case, the final concentration can be calculated as:
where, being 65 mL=0.065 L, 125 mL=0.125 L and 190 mL=0.190 L (because 1000 mL= 1 L):
- Total number of moles of solute= 0.065 L*0.513 + 0.125 L*2.33 = 0.033345 moles + 0.29125 moles= 0.324595 moles
- Total volume= 65 mL + 125 mL= 190 mL= 0.190 L
Replacing:
Final molarity ≅ 1.71
<u><em>The molar concentration of the final solution is 1.71 </em></u><u><em></em></u>
Answer: less oxygen available at higher altitudes
Explanation:
The higher in elevation you get, the lower the air pressure, allowing oxygen atoms to spread out farther, therefore making available oxygen less.
Answer:
Excess Reagent = oxygen
Explanation:
Limiting reagent: The substance that is totally consumed when the reaction is completed.
Excess reagent: The substance left after the limiting reagent is consumed completely
The balanced chemical equation for formation of water is as follow:
This means when 2 moles of hydrogen reacts with 1 mole of oxygen, 2 moles of water is produced.
Hence the ratio in which hydrogen and oxygen gas reacts is 2:1
Now if 2 mole hydrogen require 1 mole of oxygen ,then 4 mole hydrogen need 2 mole of oxygen.
or
Here 5 mole of oxygen is reacting but only 2 mole is required .
Oxygen is in excess.
Answer:
years.
Explanation:
The half-life is the time needed to reduce in 50% the mass of the sample. So, imagine compound A, after its first half-life, it will have 0.5A. After its second half-life, will have 50% of the 0.5A! So, the mass will be 0.25A. So, the percentage of A, is given by:
Where n is the quantitative of half-life. So, for 18.7% of C, or 0.187:
Applying log in both side of the equation:
nlog(0.5) = log(0.187)
-0.301n = -0.728
n = 2.419 half-life
If one half-life is 5,730 yr, than 2.419 will be:
2.419x5730 = 13,860.870 yr
years.