The percent yield : 4. 84.58%
<h3>Further explanation</h3>
Reaction
CaCO₃ ⇄ CaO+CO₂
mass CaCO₃ = 2.3 × 10³ g
mol CaCO₃ (MW=100.0869 g/mol) :
From the equation, mol CaCO₃ : CaO = 1 : 1, so mol CaO=22.98
mass CaO(MW=56.0774 g/mol)⇒ (theoretical) :
The percent yield :
A or B but i'm leaning more towards A
Answer:
the value of the equilibrium constant Kp for this reaction is 0.275
Explanation:
Step 1: Data given
Pressure HCl at the equilibrium = 18.0 atm
Pressure H2 at the equilibrium = 25.4 atm
Pressure Cl2 at the equilibrium = 46.4 atm
Step 2: The balanced equation
H2(g) + Cl2(g) → 2 HCl(g)
Step 3: Calculate the value of the equilibrium constant Kp for this reaction
Kp = (pHCl)² / (pH2*pCl2)
Kp = 18.0² / (25.4 * 46.4)
Kp = 324 / 1178.56
Kp = 0.275
the value of the equilibrium constant Kp for this reaction is 0.275
The balanced chemical reaction is:
<span>2H2+O2-->2H2O
</span>
To determine the mass of hydrogen that is needed, we need use the initial amount of oxygen and relate it to hydrogen from the reaction given. We do as follows:
192 g O2 ( 1 mol O2 / 32 g O2) ( 2 mol H2 / 1 mol O2 ) ( 2.02 g H2 / 1 mol H2 ) = 24.24 g H2
