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olga2289 [7]
3 years ago
13

Please help, I don't under stand! Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxi

dation and reduction. ____FeCl3 + ____H2S Imported Asset ____FeCl2 + ____S + ____HCl
Chemistry
1 answer:
pogonyaev3 years ago
4 0

Answer:

3 FeCl3 + H2S = 2 FeCl2 + S + 2 HCl

Explanation:

Fe goes form +3 to +2

S goes from -2 to 0

H and Cl are spectator ions

Fe3+ + 1e-= Fe2+

H2S = S + 2 H+ + 2e-

3 Fe3+ + H2S = 2 Fe2+ + S + 2 H+

3 FeCl3 + H2S = 2 FeCl2 + S + 2 HCl

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How an atom reacts chemically depends on how willing it is to share electrons with others.

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One main difference between a Prokaryotic cell and an Eukaryotic cells is __________.
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Density is d= m/vol. If a material has a mass of 65.5 g and a volume of 32.5 ml, it has a density of
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Using the given formula, the density of the material is 2.015 g/mL

<h3>Calculating Density </h3>

From the question, we are to determine the density of the material

From the given formula

Density = Mass / Volume

And from the given information,

Mass = 65.5 g

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Putting the parameters into the equation,

Density = 65.5/32.5

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8 0
2 years ago
Consider an element Z that has two naturally occuring isotopes with the following percent abundances: the isotope with a mass nu
rodikova [14]

Answer:

Z=22.70

Explanation:

It is given that,

An element Z that has two naturally occurring isotopes with the following percent abundances as follows :

The isotope with a mass number 22 is 65.0% abundant; the isotope with a mass number 24 is 35.0% abundant.

The average atomic mass for element Z is given by :

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So, the average atomic mass for element Z is 22.70.

3 0
4 years ago
47.0ml of a HBr solution were titrated with 37.5ml of a 0.215M LiOH solution to reach the equivalence point. what is the molarit
faltersainse [42]

Hello!

The molarity of the HBr solution is 0,172 M.

Why?

The neutralization reaction between LiOH and HBr is the following:

HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)

To solve this exercise, we are going to apply the common titration equation:

M1*V1=M2*V2

M1=\frac{M2*V2}{V1}= \frac{0,215 M * 37,5 mL}{47 mL}=0,172 M

Have a nice day!

4 0
3 years ago
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