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olga2289 [7]
2 years ago
13

Please help, I don't under stand! Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxi

dation and reduction. ____FeCl3 + ____H2S Imported Asset ____FeCl2 + ____S + ____HCl
Chemistry
1 answer:
pogonyaev2 years ago
4 0

Answer:

3 FeCl3 + H2S = 2 FeCl2 + S + 2 HCl

Explanation:

Fe goes form +3 to +2

S goes from -2 to 0

H and Cl are spectator ions

Fe3+ + 1e-= Fe2+

H2S = S + 2 H+ + 2e-

3 Fe3+ + H2S = 2 Fe2+ + S + 2 H+

3 FeCl3 + H2S = 2 FeCl2 + S + 2 HCl

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The pressure of the gas is expected to increase in accordance to Boyle's law.

<h3>What is Boyle's law?</h3>

Boyle's law states that, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.

By implication, when the piston is lowered and the volume of the gas is decreased, the pressure of the gas is expected to increase in accordance to Boyle's law.

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3 0
2 years ago
What is the mass of 2.071x10^14 molecules of SF2
kolezko [41]

Answer:

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No of Valence Electrons in the molecule 20

Hybridization of SF2 sp3 hybridization

Bond Angles 98 degrees

Molecular Geometry of SF2 Bent

Explanation:

Sulfur Difluoride is an inorganic molecule made up of one Sulphur atom and two Fluorine atoms. It has a chemical formula of SF2 and can be generated by the reaction of Sulphur Dioxide and Potassium Fluoride or Mercury Fluoride. In this blog post, we will look at the Lewis dot structure of SF2, its molecular geometry and shape.

7 0
3 years ago
2. The density of helium is 1.78 X 104 g/cm. What is this<br> density in Dg/um??
Zepler [3.9K]

Answer:

d=1.78\times 10^{-7}\ Dg/\mu m^3

Explanation:

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We know that,

1 g = 10 dg

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So,

d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3

So, the density of Helium is equal to 1.78\times 10^{-7}\ Dg/\mu m^3.

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2 years ago
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The answer to fill in the blank is (igneous)

I hope I helped.
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3 years ago
What experimental evidence did Thomson have for each statement?
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<span>Thomson studied electric discharge in a vacuum and found that the deflection of rays was evidence of atoms containing much smaller particles. He calculated that these particles would have a large charge in relation to their mass. While he did not name electrons, he knew they existed.</span>
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3 years ago
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