Answer:
2 possible coordinate pairs
N (8, 17) OR (-12, -3)
Step-by-step explanation:
The rule:
(x, y) => (x + 10, y + 10) OR (x - 10, y -10)
(-2 + 10, 7 + 10) OR (-2 - 10, 7 -10)
(8, 17) OR (-12, -3)
Hope this helps!
Answer:
z = x^3 +1
Step-by-step explanation:
Noting the squared term, it makes sense to substitute for that term:
z = x^3 +1
gives ...
16z^2 -22z -3 = 0 . . . . the quadratic you want
_____
<em>Solutions derived from that substitution</em>
Factoring gives ...
16z^2 -24z +2z -3 = 0
8z(2z -3) +1(2z -3) = 0
(8z +1)(2z -3) = 0
z = -1/8 or 3/2
Then we can find x:
x^3 +1 = -1/8
x^3 = -9/8 . . . . . subtract 1
x = (-1/2)∛9 . . . . . one of the real solutions
__
x^3 +1 = 3/2
x^3 = 1/2 = 4/8 . . . . . . subtract 1
x = (1/2)∛4 . . . . . . the other real solution
The complex solutions will be the two complex cube roots of -9/8 and the two complex cube roots of 1/2.
Answer:
u = 1.5
Step-by-step explanation:
5+4u=11
-5 -5
4u = 6
/4 /4
u=1.5
Answer:
3
Step-by-step explanation:
The goal is to get the x to be on one side of the equation on its own.
-6x = -18
To get rid of the -6, we would have to do the opposite of what it's doing in the equation - in this case, we would divide, as it's the opposite of multiplying.
What we do to one side of the equation, we have to do to the other.
-6x/-6 = x
-18/-6 = 3
x = 3
Hope that makes sense!
