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2 years ago

What do you call a large body of air? wind thunderstorm cold front air mass

Chemistry

2 answers:

Keith_Richards [23]2 years ago

4 0

Answer:

thunderstrom

Explanation:

it will be answer

Dovator [93]2 years ago

4 0

Answer:

air mass

Explanation:

A huge volume of air with usually constant temperature and humidity is referred to as an air mass. The properties of an air mass are determined by the place from which it originates. The longer an air mass remains above its originating region, the more damage it causes.

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or a particular isomer of C 8 H 18 , the combustion reaction produces 5104.1 kJ of heat per mole of C 8 H 18 ( g ) consumed, und

beks73 [17]

Answer:

The standard enthalpy of formation of this isomer of $C_{8}H_{18}$ is -220.1 kJ/mol.

Explanation:

The given chemical reaction is as follows.

$C_{8}H_{18}(g)+ \frac{25}{2}O_{2}(g) \rightarrow 8CO_{2}(g)+9H_{2}O(g)$

$\Delta H^{o}_{rxn}= -5104.1kJ/mol$

The expression for the entropy change for the reaction is as follows.

$\Delta H^{o}_{rxn}=[8\Delta H^{o}_{f}(CO_{2}) +9\Delta H^{o}_{f}(H_{2}O)]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}\Delta H^{o}_{f}(O_{2})]$

$\Delta H^{o}_{f}(H_{2}O)= -241.8kJ/mol$

$\Delta H^{o}_{f}(CO_{2})= -393.5kJ/mol$

$\Delta H^{o}_{f}(O_{2})= 0kJ/mol$

Substitute the all values in the entropy change expression.

$-5104.1kJ/mol=[8(-393.5)+9(-241.8)kJ/mol]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}(0)kJ/mol]$

$-5104.1kJ/mol=-5324.2kJ/mol -\Delta H^{o}_{f}(C_{8}H_{18})$

$\Delta H^{o}_{f}(C_{8}H_{18}) =-5324.2kJ/mol +5104.1kJ/mol$

$=-220.1kJ/mol$

Therefore, The standard enthalpy of formation of this isomer of $C_{8}H_{18}$ is -220.1 kJ/mol.

4 0

3 years ago

At a birthday pool party, the temperature is 28.50°C and the atmospheric pressure is 755.4 mmHg. One of the decoration helium ba

Iteru [2.4K]

Answer:

The volume of the balloon will be 5.11L

Explanation:

An excersise to solve with the Ideal Gases Law

First of all, let's convert the pressure in mmHg to atm

1 atm = 760 mmHg

760 mmHg ___ 1 atm

755.4 mmHg ____ (755.4 / 760) = 0.993 atm

922.3 mmHg ____ ( 922.3 / 760) = 1.214 atm

T° in K = 273 + °C

28.5 °C +273 = 301.5K

26.35°C + 273= 299.35K

P . V = n . R .T

First situation: 0.993atm . 6.25L = n . 0.082 . 301.5K

(0.993atm . 6.25L) / 0.082 . 301.5 = n

0.251 moles = n

Second situation:

1.214 atm . V = 0.251 moles . 0.082 . 301.5K

V = (0.251 moles . 0.082 . 301.5K) / 1.214 atm

V = 5.11L

7 0

3 years ago

Read 2 more answers

What is a saturted solution

andrew-mc [135]

Answer:

Please find the definition and further explanation below

Explanation:

Based on the ability for the solvent (liquid substance) to dissolve a solute (solid substance), a solution can either be unsaturated, saturated or supersaturated. A SATURATED SOLUTION is that which contains the maximum amount of solute a solvent can possibly dissolve.

In other words, a saturated solution can no longer dissolve anymore solute, and hence, any further solute added forms crystals or makes the solution supersaturated.

5 0

3 years ago

Is copper II chloride mixed with water an element, compound, or mixture? If it's a mixture is it homogeneous or heterogeneous?

Fittoniya [83]

Answer:

1. mixture

2. Homogenous

Explanation:

Copper II chloride is a compound because it consists of elements that are chemically combined together. When a solute in this case, copper II chloride is mixed with water- a solvent, the result is a homogenous mixture.

Homogenous substances are formed when a solute and a solvent combine, resulting in a mixture with uniform properties. Mixtures can be separated using relevant separation techniques.

7 0

3 years ago

Marissa is learning about the unique properties of waves. She has learned that whenever the wavelength of a wave increases, the

Goshia [24]

Answer:

I believe it is B

Explanation:

4 0

3 years ago