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sergeinik [125]
2 years ago
6

Enter the number 0.000354 in scientific notation

Chemistry
1 answer:
Yakvenalex [24]2 years ago
3 0

Answer:

The scientific notation is 3.54 × 10^-4

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KI is the formula to potassium
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If you can continue to add more solute to a solution, the solution is said to be ____________________
Savatey [412]

Answer:

Unsaturated

Explanation:

In order to successfully answer this question, we need to think about the solubility of solutes in specific solvents, typically water.

  • A solution is considered to be unsaturated if at a given temperature and volume of water we may still add more solute and it will dissolve;
  • A solution is considered to be saturated if at a given temperature and volume of water we have a maximum amount of solute dissolved and trying to add more solute results in undissolved crystals that can be seen in the solution;
  • A solution is considered to be oversaturated (or supersaturated) i at a given temperature and volume of water we exceeded the maximum amount of a solute that could possibly dissolve.

In this case, if we can continue to add more solute to a solution and the solute dissolves, we may state that we are still at a point in which we have an unsaturated solution.

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How many moles of oxygen will be produced from the decomposition of 3 moles of KClO3?
AlexFokin [52]

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4.5moles

Explanation:

First, let us balance the equation given from the question. This is illustrated below:

KClO3 —> KCl + O2

There are 2 atoms of O on the right side and 3 atoms on the left. It can be balance by putting 2 in front of KClO3 and 3 in of O2 as shown below

2KClO3 —> KCl + 3O2

Now, we have 2 atoms each of K and Cl on the left side and 1atom each of K and Cl on the right. It can be balance by putting 2 in front of KCl as shown below:

2KClO3 —> 2KCl + 3O2

Now the equation is balanced.

From the balanced equation,

2 moles of KClO3 produced 3 moles of O2.

Therefore, 3 moles of KClO3 will produce = (3 x 3) /2 = 4.5moles of O2.

Therefore 3 moles of KClO3 will produce 4.5 moles of O2

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