All categories

3 years ago

A carbon-carbon triple bond is found in a molecule of

2 answers:

5 0

The answer is (4) butyne. The carbon-carbon triple bond is found in alkynes. And the alkynes has -yne at the end of the name. "-ene" end means that it is alkene and has carbon-carbon double bonds.

jolli1 [7]3 years ago

5 0

Answer: Option (4) is the correct answer.

Explanation:

A hydrocarbon in which all atoms are bonded by single bond and have a general formula $C_{n}H_{2n+2}$ is known as an alkane.

A suffix "ane" adds at the end of the name of this hydrocarbon.

A hydrocarbon in which an atom is bonded by a double bond and have a general formula $C_{n}H_{2n}$ is known as an alkene.

A suffix "ene" adds at the end of the name of this hydrocarbon.

A hydrocarbon in which an atom is bonded by triple bond and have a general formula $C_{n}H_{2n-2}$ is known as an alkene.

A suffix "yne" adds at the end of the name of this hydrocarbon.

Thus, we can conclude that a carbon-carbon triple bond is found in a molecule of butyne.

You might be interested in

Don’t understand this science Question.

stepladder [879]

What is the question?

6 0

2 years ago

Read 2 more answers

Calculate hydrochloric acid (umol)in 200 ul of a 0.5173Msolution of acid?

strojnjashka [21]

Answer: The moles of hydrochloric acid is $1.0346\times 10^{-4}\mu mol$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Micro moles of solute}\times 10^6}{\text{Volume of solution (in }\mu L)}}$

We are given:

Molarity of solution = 0.5173 M

Volume of solution = $200\mu L$

Putting values in above equation, we get:

$0.5173M=\frac{\text{Micro moles of HCl}\times 10^6}{200\mu L}\\\\\text{Micro moles of HCl}=1.0346\times 10^{-4}\mu mol$

Hence, the moles of hydrochloric acid is $1.0346\times 10^{-4}\mu mol$

7 0

2 years ago

What type of compound is CaBr2 ?

kirza4 [7]

Answer:

Calcium bromatum

Explanation:

3 0

3 years ago

Read 2 more answers

A 25.00 ml sample of h3po4 solution is neutralized by exactly 54.93 ml of 0.04345 m ca(oh)2. what is the molarity of the h3po4 s

son4ous [18]

The neutralization equation is:
3 Ca(OH)₂ + 2 H₃PO₄ → Ca₃(PO₄)₂ + 6 H₂O

From this equation we can see that 3 moles of Ca(OH)₂ react with 2 moles of H₃PO₄

Numbers of mmol of Ca(OH)₂ = M x V = 0.04345 x 54.93 = 2.387 mmol

Number of mmol of H₃PO₄ = 2.387 x (2/3) = 1.591 mmol

Molarity of solution = n (mmol) / V(ml) = 1.591 / 25 = 0.0636 M

8 0

3 years ago

Read 2 more answers

CH3COOH

Nutka1998 [239]

Answer:

the water which are very healthy is known as hydrated water

8 0

3 years ago