Question

The sample mean tip amount for the 20 parties to which the waitress gave her name was $5.44, with a standard deviation of $1.75. These statistics were $3.49 and $1.13, respectively, for the 20 parties to which the waitress did not give her name. The data were not strongly skewed in either group.
Required:
Use appropriate symbols for the six numbers reported in this paragraph.

Answer 1

Answer:

First sample size, $n_{x}$ = 20

Second sample size, $n_{y}$ = 20

Sample mean of first sample, $\bar{x}$ = 5.44

Sample mean of second sample, $\bar{y}$ = 3.49

Sample Standard deviation of first sample, $\sigma_{x}$ = 1.75

Sample Standard deviation of second sample, $\sigma_{y}$ = 1.13

Step-by-step explanation:

Given - The sample mean tip amount for the 20 parties to which the waitress gave her name was $5.44, with a standard deviation of $1.75. These statistics were $3.49 and $1.13, respectively, for the 20 parties to which the waitress did not give her name. The data were not strongly skewed in either group.

To find - Use appropriate symbols for the six numbers reported in this paragraph.

Proof -

First sample size, $n_{x}$ = 20

Second sample size, $n_{y}$ = 20

Sample mean of first sample, $\bar{x}$ = 5.44

Sample mean of second sample, $\bar{y}$ = 3.49

Sample Standard deviation of first sample, $\sigma_{x}$ = 1.75

Sample Standard deviation of second sample, $\sigma_{y}$ = 1.13