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2 years ago

PLS HELP AND NO LINKS PLS What place is affected by acid rain and why?

Chemistry

1 answer:

Greeley [361]2 years ago

6 0

Answer:

Acid rain is responsible for severe environmental destruction across the world and occurs most commonly in the North Eastern United States, Eastern Europe and increasingly in parts of China and India

Explanation:

hope this answer will help you

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Nitrogen and oxygen form an extensive series of oxides with the general formula NxOy. One of them is a blue solid that comes apa

Marizza181 [45]

Work out the number of moles in

100.00 grams of the oxide.

For nitrogen: The atomic mass of N is 14.0067, and we have 36.84 g N:

36.84 g N14.0067 g N/mol N=2.630 mol N

For oxygen: The atomic mass of O is

15.9994, and we have

100.00−36.84=63.16 g O:

63.16 g N 15.9994 g N/mol N=3.948 mol N

Now the ratio 3.958 2.630 is very close to

1.5=32

. So we conclude that the gas has three moles

O to two moles N making the empirical formula

N2O3.

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5 0

2 years ago

A substance floats or sinks in another because of its relative

almond37 [142]

Its relative density causes objects to float or sink.
If the density of the substance is greater than the substance it is in, it will sink.
If the density is less than the substance it is in it will float.

5 0

2 years ago

HELP really struggling with this one

Evgen [1.6K]

Answer:

the answer is B no need to struggle ur answer is correct

8 0

1 year ago

HELP ME, REDOX REACTION AND OXIDATION NUMER. NO LINKS PLEASE THEY DONT WORK

cricket20 [7]

Answer:

Huh can you explain with more detail

3 0

2 years ago

A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600.mL at 1.0atm. To prepare for ignition of

Ket [755]

12 atm is the new pressure of the air‑fuel mixture when A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600 ml at 1.0atm and final volume of 50 ml.

Explanation:

Data given:

The air fuel mixture is assumed to be having ideal behaviour

initial volume of gaseous air fuel mixture V1 = 600 ml

initial pressure of gaseous air fuel mixture P1= 1 atm

final volume when piston is removed, V2= 50 ml

final pressure of the gaseous air mixture, P2 = ?

Applying the Boyle's Law,

P1V1 = P2V2

rearranging the equation:

P2 = $\frac{P1V1}{V2}$

putting the value in the equation,

P2 = $\frac{600 X 1}{50}$

P2 = 12 atm

the pressure is increased to 12 atm when volume is reduced to 50 ml.

7 0

2 years ago