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Olenka [21]
3 years ago
12

The density of mercury is 5,427 kg/m3. If the density of water is 1.0 g/mL, will mercury float or sink in water?

Chemistry
2 answers:
Licemer1 [7]3 years ago
6 0

Mercury will sink because the destiny of mercury is 5.427 g/mL, which is greater than the 1.0g/mL density of water.

Ksenya-84 [330]3 years ago
3 0
1 kg =1000 g = 10³ g,
1 m = 100 cm  ,
(1m)³  = (100 cm)³= (10²)³ cm³ = 10⁶ cm³  or 10⁶ mL

5,427 kg/m³ = <span>5,427 kg/ 1m³ = (5427 * 10³ g)/ 10⁶ mL=5427/10³ g/mL=
=5427/1000 g/mL = 5.427 g/mL 

</span>5.427 g/mL   is density of Mercury, and 1.0 g/mL is density  of water.
Density of Mercury is more then density of the water, so
mercury will sink in the water.
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katovenus [111]
I think the answer is C. Hope this helped. 
6 0
3 years ago
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crimeas [40]

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cytoplasm is A, Dna is C, and nucleas is B

Explanation:

3 0
3 years ago
Write a word equation for the combustion of propane???<br> HELP????
frutty [35]

Answer:

1 mole of propane combines with 5 moles of oxygen gas to produce 3 mole of carbon dioxide and 4 moles of water.

Explanation:

The word equation for the combustion of propane can be obtained from the chemical equation;

      C₃H₈   +    5O₂    →   3CO₂   +   4H₂O  

The word equation is therefore:

 1 mole of propane combines with 5 moles of oxygen gas to produce 3 mole of carbon dioxide and 4 moles of water.

For such a combustion reaction, carbon dioxide and water are produced in the process.

8 0
3 years ago
Calculate the area of a 3.0 inch by 5.0 inch index card in square millimeters (mm). (You can look up the formula for the area of
meriva

Answer:

The area of the given rectangular index card = <u>9677.4 mm²</u>    

Explanation:

Area is defined as the space occupied by a two dimensional shape or object. The SI unit of area is square metre (m²).

<u>The area of a rectangle</u> (A) =  length (l) × width (w)

Given dimensions of the rectangle: Length (l) = 5.0 inch, Width (w) = 3.0 inch

Since, 1 inch = 25.4 millimetres (mm)

Therefore, l = 5 × 25.4 = 127 mm, and w = 3 × 25.4 = 76.2 mm

Therefore, <u>the area of the given rectangular index card</u> = A= l × w = 127 mm × 76.2 mm = <u>9677.4 mm²</u>

5 0
3 years ago
If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?
Vilka [71]

Answer:

A = 349 g.

Explanation:

Hello there!

In this case, since the radioactive decay kinetic model is based on the first-order kinetics whose integrated rate law is:

A=Ao*exp(-kt)

We can firstly calculate the rate constant given the half-life as shown below:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{58year}=0.012year^{-1}

Therefore, we can next plug in the rate constant, elapsed time and initial mass of the radioactive to obtain:

A=500g*exp(-0.012year^{-1} *30year)\\\\A=349g

Regards!

5 0
3 years ago
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