1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olenka [21]
3 years ago
12

The density of mercury is 5,427 kg/m3. If the density of water is 1.0 g/mL, will mercury float or sink in water?

Chemistry
2 answers:
Licemer1 [7]3 years ago
6 0

Mercury will sink because the destiny of mercury is 5.427 g/mL, which is greater than the 1.0g/mL density of water.

Ksenya-84 [330]3 years ago
3 0
1 kg =1000 g = 10³ g,
1 m = 100 cm  ,
(1m)³  = (100 cm)³= (10²)³ cm³ = 10⁶ cm³  or 10⁶ mL

5,427 kg/m³ = <span>5,427 kg/ 1m³ = (5427 * 10³ g)/ 10⁶ mL=5427/10³ g/mL=
=5427/1000 g/mL = 5.427 g/mL 

</span>5.427 g/mL   is density of Mercury, and 1.0 g/mL is density  of water.
Density of Mercury is more then density of the water, so
mercury will sink in the water.
You might be interested in
Poh of a solution with a ph of 5.00
creativ13 [48]

Answer:

9

Explanation:

14-5.=pOH

- Hope that helps! Please let me know if you need further explanation.

8 0
3 years ago
A vector is represented as a ____​
monitta
I hope this helped you have a good day

3 0
2 years ago
A chemical reaction at equilibrium always has _______.
natka813 [3]

Answer:

A

Explanation:

3 0
2 years ago
I need to know the answer for number two. * I
snow_lady [41]

Answer:

The answer to your question is (C). I would work out the question for you lad, but I don't know how to do it on here.

Explanation:

7 0
3 years ago
A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 17.14 mL of 0.04907 M EDTA to reach the end point. A 50
dolphi86 [110]

Answer:

pAl³⁺ = 1,699

pPb²⁺ = 1,866

Explanation:

In this problem, the first titration with EDTA gives the moles of Al³⁺ and Pb²⁺, these moles are:

Al³⁺ + Pb²⁺ in 25,00mL = 0,04907M×0,01714L = <em>8,411x10⁻⁴ moles of EDTA≡ moles of Al³⁺ + Pb²⁺.</em>

The molar concentration is <em>8,411x10⁻⁴ moles/0,02500L = </em><em>0,0336M Al³⁺+Pb²⁺.</em>

In the second part each Al³⁺ reacts with F⁻ to form AlF₃. Thus, you will have in solution just Pb²⁺.

The moles added of EDTA are:

0,02500L×0,04907M = 1,227x10⁻³ moles of EDTA

The moles of EDTA in excess that react with Mn²⁺ are:

0,02064M × 0,0265L = 5,470x10⁻⁴ moles of Mn²⁺≡ moles of EDTA

That means that moles of EDTA that reacted with Pb²⁺ are:

1,227x10⁻³ moles - 5,470x10⁻⁴ moles = 6,800x10⁻⁴ moles of EDTA ≡ moles of Pb²⁺.

The molar concentration of Pb²⁺ is:

6,800x10⁻⁴mol/0,0500L = <em>0,0136 M Pb²⁺</em>

Thus, molar concentration of Al³⁺ is:

0,0336M Al³⁺+Pb²⁺ - 0,0136 M Pb²⁺ = <em>0,0200M Al³⁺</em>

pM is -log[M], thus pAl³⁺ and pPb²⁺ are:

<em>pAl³⁺ = 1,699</em>

<em>pPb²⁺ = 1,866</em>

I hope it helps!

3 0
2 years ago
Other questions:
  • Explain the changes that take place at the molecular level when a substance is superheated or supercooled ?
    13·1 answer
  • Fill in the coefficients that will balance the following reaction:
    8·1 answer
  • How does having no nucleus effect an rcbs life span?
    12·1 answer
  • What is the special state of matter that exist last at extremely high temperatures?
    6·1 answer
  • What term refers to the small parts of a cell that carry out different functions?
    10·1 answer
  • Which units express heat capacity
    14·2 answers
  • All matter has mass and takes up space.<br> True<br> False
    9·1 answer
  • Why is pseudo science not considered real science
    11·1 answer
  • The following is an example of which type of boundary?
    12·1 answer
  • Draw structures from the following names, and determine which compounds are optically active:(c) 1,2-dibromo-2-methylbutane
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!