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Olenka [21]
3 years ago
12

The density of mercury is 5,427 kg/m3. If the density of water is 1.0 g/mL, will mercury float or sink in water?

Chemistry
2 answers:
Licemer1 [7]3 years ago
6 0

Mercury will sink because the destiny of mercury is 5.427 g/mL, which is greater than the 1.0g/mL density of water.

Ksenya-84 [330]3 years ago
3 0
1 kg =1000 g = 10³ g,
1 m = 100 cm  ,
(1m)³  = (100 cm)³= (10²)³ cm³ = 10⁶ cm³  or 10⁶ mL

5,427 kg/m³ = <span>5,427 kg/ 1m³ = (5427 * 10³ g)/ 10⁶ mL=5427/10³ g/mL=
=5427/1000 g/mL = 5.427 g/mL 

</span>5.427 g/mL   is density of Mercury, and 1.0 g/mL is density  of water.
Density of Mercury is more then density of the water, so
mercury will sink in the water.
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3.65 gram of hcl is dissolved in 180 gram of water. Find the total number of molecules of hydrogen​
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Molec_{\ H_{tot}}=1.206x10^{25}molec

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH}  =6.03x10^{22}molec

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH}  =1.20x10^{25}molec

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