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3 years ago

Can someone help me please

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

4 0

Answer:

Substitute the 80°F where the F is in the equation. then just put the whole equation into your calculator. I got approximately 26.7.

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F(x) = 1/3x² – 3x² – 7 What kind o

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Answer:f ( x - 1 ) = 3x² - 5x - 7

Step-by-step explanation:

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3 years ago

Find x A. 22√2 B. 22 C. 11√3/3 D. 11√3

mel-nik [20]

Answer

$22\sqrt{2}$

Step-by-step explanation:

First we gave a name to the side that is common for both triangles, can be Y for example.

Using trigonometric functions we can make a relationship between the two angles that we have and the magnitud of the side.

$sin(45)=\frac{11}{Y} \\$ , Because sin(x)= op/hip

$cos(60)=\frac{Y}{x}$ , Because con(x)=ad/hip

Having this equations, we can solve the system and find x

$Y=\frac{11}{sin(45)} \\Y=cos(60)*x$

we equal Y and solve

$\frac{11}{sin(45)}=cos(60)*x\\ x=\frac{11}{sin(45)*cos(60)} \\x=\frac{11}{\frac{\sqrt{2} }{2} *\frac{1}{2} } \\x=\frac{11}{\frac{\sqrt{2} }{4} } \\x=\frac{44}{\sqrt{2} }\\$

Then we rationalize

$x=22\sqrt{2}$

Hope you like it!

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3 years ago

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What is 500 - 200. please answer.

Assoli18 [71]

Answer:

300

Step-by-step explanation:

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If 14 g of a radioactive substance are present initially and 7 yr later only 7 g remain, how much of the substance will be pres

Delvig [45]

Answer:

2.60 gr

Step-by-step explanation:

We need to consider the function $P(t) = P_oe^{kt}$ where Po is the initial substance k is the rate of decay and t is the time

We know that $P_o = 14$ and at the 7 th year P(t) is 7

This means

$7 = 14e^{7k}$

We solve for k

$\frac{7}{14} = e^{7k}\\\\\ln (\frac{7}{14}) = 7k\\\\k = \frac{\ln (7/14)}{7} = -0.099\\\\Then \ P(t) = 14e^{-0.099t}\\\\Now \ we \ take \ t = 17\\\\P(17) = 14e^{(-0.099)(17)} = 2.60$

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3 years ago

For people who need points

dem82 [27]

Answer:

thanks for god bless you

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3 years ago

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