3 years ago

Can someone help me please

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

4 0

Answer:

Substitute the 80°F where the F is in the equation. then just put the whole equation into your calculator. I got approximately 26.7.

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Every month, Edmund saves some money and puts the money into a bag. The bag now contains some $2, $5 and $10 notes with the tota

Readme [11.4K]

Answer:

186

Step-by-step explanation:

$2x+10(312)+58(5)=3782$

$2x+3410=3782$

$2x=372$

$x=186$

6 0

3 years ago

6(x-8)+10=5x-6 This question has how many solutions

alina1380 [7]

Answer:

x=32 so one solution only

Step-by-step explanation:

6(x-8)+10=5x-6

6x-48+10=5x-6

6x-38=5x-6

x-38=-6

x=32

Therefore, the equation only has one solution which is x=32

4 0

3 years ago

Read 2 more answers

Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how

astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was $95,300.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be $x.$

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

$x=A\times (1+\frac{r}{100})^{11}$

$x=75000\times (1+\frac{2.2}{100})^{11}$

$x=75000\times (1+0.022)^{11}$

$x=75000\times (1.022)^{11}$

$x=75000\times 1.2704$

$x=95280.$

The amount of house after eleven years to the nearest hundred dollars is $95,300.

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0

3 years ago

Help me pls :((((((((((((((((((( /

AveGali [126]

1= -72 ( negative 72)

3 0

3 years ago

What is the value of m? m3 = 64

uranmaximum [27]

Answer

m=4

Step-by-step explanation:

3 0

3 years ago