4a + 2b = 10
you are solving for b
isolate the b
subtract 4a from both sides
4a (-4a) + 2b = 10 (-4a)
2b = 10 - 4a
divide 2 from both sides to isolate the b
2b(/2) = (10 - 4a)/2
b = (10 - 4a)/2
b = 5 - 2a
C) b = -2a + 5 is your answer
hope this helps
Answer:
192 orders
Step-by-step explanation:
All robots are working simultaneously, so each robot takes 10 minutes to do their orders. They are all identical, so they take an equal amount of time to do each order, meaning 20 ÷ 5 = 4. Each robot takes 10 minutes to do 4 orders.
If there are eight robots working for 60 minutes, each robot can make six times as many orders, compared to when they were working for 10 minutes. 4 x 6 = 24. There are eight robots, so 24 x 8 = 192 orders.
QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
