I think it is 15 so I don’t know that if it right
Answer:
c. jasper has apparently decreased the volume of items in his ending inventory as compared to the number of items in his beginning inventory
Step-by-step explanation:
First In First Out FIFO is a type of inventory system in accounting, it literally implies that the oldest purchase goes out first when you made a sale. The oldest purchase are charged based on cost of good sold. If price are rising, :
FIFO will yield a lower cost of good sold
FIFO will yield a higher net income
FIFO will yield higher tax liability
FIFO will yield a higher inventory
From the information given:
the business records show that the cost of the stores inventory items has been steadily increasing. the cost of the end of the year inventory is 200,000 and the cost of the beginning of the year inventory was 250,000.
What the statement implies is that:
jasper has apparently decreased the volume of items in his ending inventory as compared to the number of items in his beginning inventory
Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:

Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:

That's 1/4 of a minute which is 15 seconds.
Positive because you will said that has the charged is about $2.50