Answer:
Step-by-step explanation:
Let's solve for f.
y=3x−2x2findf(3)
Step 1: Flip the equation.
−6df2inx2+3x=y
Step 2: Add -3x to both sides.
−6df2inx2+3x+−3x=y+−3x
−6df2inx2=−3x+y
Step 3: Divide both sides by -6dinx^2.
−6df2inx2
−6dinx2
=
−3x+y
−6dinx2
f2=
3x−y
6dinx2
Step 4: Take square root.
f=√
3x−y
6dinx2
or f=−√
3x−y
6dinx2
Answer:
f=√
3x−y
6dinx2
or f=−√
3x−y
6dinx2
The total cost would be $191.49
Not rounded up so round it up to .50 if you have to :)
Answer:
pethagoru
8^2 + 6^2= 100
pethagorus theory is a^2+b^2=c^2.
a^2 = base
b^2= side
c^2= hypotenuse
Answer:
There is no solution to this problem.
Step-by-step explanation:
The 1 digit number cannot be 1, since there would be no remainder.
The 1 digit number cannot be 2, since the remainder could be 0 or 1.
The 1 digit number cannot be 3, since the remainder could be 0, 1, or 2.
So, the 1 digit number must be greater than 3. Let's start with 4. Since the quotient is 307 (remainder 3), 4 x 307 is already more than 3 digits.
The answer will be Y=6*5=30
