Answer:
42.5 m/s
Explanation:
Given:
x₀ = 0 m
x = 62 m
y₀ = 80 m
y = 0 m
v₀ᵧ = 0 m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
Find: v
First, find the time it takes to land.
y = y₀ + v₀ᵧ t + ½ aᵧ t²
(0 m) = (80 m) + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 4.04 s
Find the horizontal component vₓ:
x = x₀ + vₓ t − ½ aₓ t²
(62 m) = (0 m) + vₓ (4.04 s) − ½ (0 m/s²) (4.04 s)²
vₓ = 15.3 m/s
Find the vertical component vᵧ:
vᵧ = aᵧ t + v₀ᵧ
vᵧ = (-9.8 m/s²) (4.04 s) + (0 m/s)
vᵧ = -39.6 m/s
Find the speed using Pythagorean theorem:
v = √(vₓ² + vᵧ²)
v = √((15.3 m/s)² + (-39.6)²)
v = 42.5 m/s
Answer:
The west component of the given vector is - 42.548 meters.
Explanation:
We need to translate the sentence into a vectoral expression in rectangular form, which is defined as:
Where:
- Horizontal component of vector distance, measured in meters.
- Vertical component of vector distance, measured in meters.
Let suppose that east and north have positive signs, then we get the following expression:
![(x, y) = (-45\cdot \cos 19^{\circ}, -45\cdot \sin 19^{\circ})\,[m]](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-45%5Ccdot%20%5Ccos%2019%5E%7B%5Ccirc%7D%2C%20-45%5Ccdot%20%5Csin%2019%5E%7B%5Ccirc%7D%29%5C%2C%5Bm%5D)
![(x, y) = (-42.548,-14.651)\,[m]](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-42.548%2C-14.651%29%5C%2C%5Bm%5D)
The west component corresponds to the first component of the ordered pair. That is to say:
The west component of the given vector is - 42.548 meters.
Answer:
a. distance = s x t
Explanation:
The equation we know for speed is speed = distance/time, shortened to s = d/t
If you want to find the distance, you'd rearrange the formula to make d the subject. To isolate d, multiply by t on both sides (since it's being divided on the right. This leads to
s x t = d, with d isolated on the right side.
Therefore, to find the distance an object travelled you'd use a. distance = s x t
