All categories

4 years ago

Explain how a gene pool and biological evolution are related

1 answer:

7 0

The ones that are able to survive pass on their genes to the next generation. Bye doing that they pass on certain traits to the next generation causing them to inherit those traits and develop new ones and that prosses repeats for thousands and millions of years and that's how they are able to evolve.

You might be interested in

How many moles of iron would be needed to react with 3.82 moles of oxygen

Rashid [163]

Answer:

5.09

Explanation:

8 0

3 years ago

Interpreting the periodic table

Goryan [66]

Here is an image of the periodic table. Hope this helps.

6 0

3 years ago

Why does water evaperate

Juli2301 [7.4K]

Explanation:

water evaporates because when h2o (water) particles heat up, they gain energy causing them to start to vibrate. this moves the oarticles further and further away from eachother and making the substance less dense, and turning it into a gas. meaning it has evaporated

5 0

2 years ago

Read 2 more answers

You are asked to prepare 500 mL 0.300 M500 mL 0.300 M acetate buffer at pH 4.904.90 using only pure acetic acid ( MW=60.05 g/mol

defon

Answer:

You will need 9,0 g of acetic acid

Explanation:

The equilibrium acetate-acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka = 4,76

Using Henderson-Hasselbalch you will obtain:

pH = pka + log₁₀ $\frac{[A^{-}]}{[HA]}$

Where HA is acetic acid and A⁻ is acetate ion

4,90 = 4,76 + log₁₀ $\frac{[A^{-}]}{[HA]}$

1,38 = $\frac{[A^{-}]}{[HA]}$ (1)

As acetate concentration is 0,300M:

0,300M = [HA] + [A⁻] (2)

Replacing (2) in (1):

[HA] = 0,126 M

And:

[A⁻] = 0,174 M

As you need to produce 500 mL:

0,5 L × 0,126 M = 0,063 moles of acetic acid

0,5 L × 0,174 M = 0,087 moles of acetate

To produce moles of acetate from acetic acid:

CH₃COOH + NaOH → CH₃COO⁻ + Na⁺ + H₂O

Thus, moles of acetate are equivalents to moles of NaOH and all acetates comes from acetic acid, thus:

0,087 moles of acetate + 0,063 moles of acetic acid ≡ 0,15 moles of acetic acid × $\frac{60,05 g}{1mol}$ = 9,0 g of acetic acid

I hope it helps!

5 0

3 years ago

If 5 grams of co and 5 grams of o2 are combined according to the reaction 2co o2 --> 2co2, which is the limiting reagent?

IrinaK [193]

When 5 grams of CO and 5grams of O₂ is combined according to the reaction 2CO + O₂ ----------> 2CO₂ then Limiting reagent is CO.

Limiting reagent is the reactant that get used up in the reaction first.

According to the given reaction:

2CO + O₂ ----------> 2CO₂

5g 5g

∴ Molar mass of CO = Molar mass of C + Molar mass of O

⇒ Molar mass of CO = 14 + 16

⇒ Molar mass of CO = 28g

∴ Molar mass of O₂ = 16(2) = 32g

∴ Molar mass of CO₂ = Molar mass of C + 2(Molar mass of O)

⇒ Molar mass of CO₂ = 14 + 2(16)

⇒Molar mass of CO₂ =44g

Let's find out the moles of CO and O₂

∴ Moles = Given mass / Molar mass

⇒ moles of CO = 5/28 = 0.17

⇒ moles of O₂ = 5/32 = 0.15

For finding out the Limiting Reagent, we will divide the number of moles with the stiochiometry of the given reaction.

⇒ For CO = Moles/ stiochiometry = 0.17/2 = 0.085

⇒ For O₂ = Moles/ stiochiometry = 0.15/1 = 0.15

Since, the ratio of number of moles with the stiochiometry is less for CO hence it is the Limiting reagent, i.e. it will get used up in the reaction first.

Hence, the Limiting reagent for the reaction is CO.

Learn more about Limiting reagent here, brainly.com/question/11848702

#SPJ4

8 0

1 year ago