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3 years ago

Not all solutions are solids dissolved in liquids. Provide 2 examples of other types of solutions.

1 answer:

7 0

<span>A substance only dissolves if the attraction between the particles of the solute and the solvent is enough to overcome the attraction of the particles of each substance for others of the same type. For instance, the attraction between the ions in table salt and water molecules is enough to both pull individual ions away from the salt crystal and to separate the water molecules to accommodate the ions. Benzene, on the other hand, does not attract the ions of salt strongly enough to remove them from the crystals. Napthalene does not dissolve in water because napthalene does not exert a strong enough attraction to water molecules to separate them and make room for itself.</span>

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Calculate the number of moles in a 14.5 gram sample of C4H10.

cricket20 [7]

Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
= 58.14g/mol

Moles=14.5g / 58.14g/mol
=0.249

Therefore there are approx 0.249 moles in a 14.5g sample of C4H10

6 0

3 years ago

If the fugacity of a pure component at the conditions of an ideal solution is 40 bar and its mole fraction is 0.4, what is its f

yaroslaw [1]

Answer : The fugacity in the solution is, 16 bar.

Explanation : Given,

Fugacity of a pure component = 40 bar

Mole fraction of component = 0.4

Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.

Now we have to calculate the fugacity in the solution.

Formula used :

$f_i=X_i\times f_i^o$

where,

$f_i$ = fugacity in the solution

$f_i^o$ = fugacity of a pure component

$X_1$ = mole fraction of component

Now put all the give values in the above formula, we get:

$f_i=0.4\times 40\text{ bar}$

$f_i=16\text{ bar}$

Therefore, the fugacity in the solution is, 16 bar.

4 0

3 years ago

In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is

V125BC [204]

Answer:

the Molar heat of Combustion of diphenylacetylene $(C_{14}H_{10})$ = $-6.931 *10^3 \ kJ/mol$

Explanation:

Given that:

mass of diphenylacetylene $(C_{14}H_{10})$ = 0.5297 g

Molar Mass of diphenylacetylene $(C_{14}H_{10})$ = 178.21 g/mol

Then number of moles of diphenylacetylene $(C_{14}H_{10})$ = $\frac{mass}{molar \ mass}$

= $\frac{0.5297 \ g }{178.24 \ g/mol}$

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene $(C_{14}H_{10})$ = Heat absorbed by $H_2O$ + Heat absorbed by the calorimeter

Heat liberated by 0.002972 mole of diphenylacetylene $(C_{14}H_{10})$ = msΔT + cΔT

= 1369 g × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene $(C_{14}H_{10})$ = 20598.87 J

Heat liberated by 1 mole of diphenylacetylene $(C_{14}H_{10})$ will be = $\frac{20598.87 \ J}{0.002972 \ mol}$

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of Combustion of diphenylacetylene $(C_{14}H_{10})$ = $-6.931 *10^3 \ kJ/mol$

3 0

3 years ago

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Calculate the ionic strength of a solution of iron (iii) carbonate, fe2(co3)3 of concentration 0.020 mol dm

Ede4ka [16]

E=b(x^3)×co3x{fe2}+13^3

6 0

3 years ago

17)<br> How many grams are in 0.02 moles of beryllium iodide, Bel2?

Alinara [238K]

Answer:

beryllium iodide has a molar mass of 262.821 g mol−1 , which means that 1 mole of beryllium iodide has a mass of 262.821 g . To find the mass of 0.02 moles of beryllium iodide, simply multiply the number of moles by the molar mass in conversion factor form.

Explanation:

5 0

3 years ago

Read 2 more answers