A temperature unit is known as a _____. <br> kilogram<br> calorie<br> joule <br> kelvin

(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.

Temka [501]

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

$BW = F_{c2}-F_{c1}$

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

$BW = (88-5)kHz$

$BW = 83kHz$

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

$f_0 = \sqrt{f_{c1}*f_{c2}}$

$f_0 = \sqrt{88*5}$

$f_0 = 20.97kHz$

7 0

3 years ago

What describes why ocean currents are considered convection currents

ratelena [41]

Convection occurs because the oceanic waters heat up becoming less dense. This water moves above the cooler water, and give off its heat to the surrounding environment. As it cools, it begins to sink, and the process begins again.

8 0

4 years ago

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A Jamaican Bobsled team hits the brakes on their sled so that decelerates at a uniform rate of 0.43 m/s^2. How long does it take

ankoles [38]

Answer:

20.05 seconds

Explanation:

Given that:

v² = u² + 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance

a = negative acceleration = - 0.43

s = distance = 86.5

v = 0

0 - 2(0.43)(86.5) = u²

74.39 = v²

U = sqrt(74.39)

U = 8.6249

From ;

t = Time in seconds

t = (v - u) / a

t = (0 - 8.6249) / - 0.43

t = 20.057

6 0

3 years ago

A 0.453 kg pendulum bob passes through the lowest part of its path at a speed of 2.58 m/s. What is the tension in the pendulum c

harkovskaia [24]

Answer with Explanation:

Mass of pendulum bob, m=0.453 kg

Speed, $v_1=$ 2.58 m/s

a.r=75.1 cm= $75.1\times 10^{-2}m$ =0.751 m

$1cm=10^{-2} m$

Tension in the pendulum cable is given by

Tension=Centripetal force+force due to gravity

$T=\frac{mv^2}{r}+mg$

Where $g=9.8 m/s^2$

Substitute the values

$T=\frac{0.453(2.58)^2}{75.1\times 10^{-2}}+0.453\times 9.8$

$T=8.45 N$

b.When the pendulum reaches its highest point,then

Final velocity, $v_2=0$

According to law of conservation of energy

$mgh_1+\frac{1}{2}mv^2_1=mgh_2+\frac{1}{2}mv^2_2$

$gh_1+\frac{1}{2}v^2_1=gh_2+\frac{1}{2}v^2_2$

$h_1=0$

Substitute the values

$9.8\times 0+\frac{1}{2}(2.58)^2=9.8\times h_2+\frac{1}{2}(0)^2$

$3.3282=9.8h_2$

$h_2=\frac{3.3282}{9.8}=0.34 m$

The angle mad by cable with the vertical= $cos\theta=\frac{0.751-0.34}{0.751}=0.55$

$\theta=cos^{-1}(0.55)=56.6^{\circ}$

c.When the pendulum reaches at highest point then

Acceleration, a=0

Therefore, the tension in the pendulum cable

$T=mgcos\theta$

Substitute the values

$T=0.453\times 9.8cos56.6$

$T=2.4 N$

8 0

3 years ago

Describe by using the atomic model as an example, the usefulness of models in science.

Nina [5.8K]

Models help in the visualization and understanding of a phenomenon. For example, the atomic model helped scientists understand the arrangement of protons, neutrons and electrons in the atom long before it could be observed and this helped them relate the structure to its effects.

7 0

3 years ago

A temperature unit is known as a _____. kilogram calorie joule kelvin