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andrew11 [14]
3 years ago
13

A rock is thrown straight downward from a tree limb with an initial velocity v0. The rock has constant downward acceleration of

10 m/s2 during its fall. The rock moves 7 times as far during the first 3 seconds as during the first 1 second of fall. What is the value (magnitude only) of v0?
Physics
1 answer:
viktelen [127]3 years ago
3 0

Answer:

v₀ = 15 m/s

Explanation:

given,

initial velocity = v₀

down acceleration of rock = 10 m/s²

rock distance

  S₄ = 7 x S₁

From kinematic equations

S = v₀ t+0.5 at²

at t = 1 s

S₁ = v₀ (1)+0.5 x 10 x 1²

S₁ = v₀+ 5......(1)

at t = 4 s

 S₄ = v₀ (4)+0.5 x 10 x 4²

 S₄ = 4 v₀+80.....(2)

from equation (1) and  (2)  

7( v₀ + 5 ) = 4 v₀ +80

3 v₀ = 80 - 35

3 v₀ = 45

v₀ = 15 m/s

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A charge of 0.91 C is spread uniformly throughout a 25 cm rod of radius 4 mm. What are the volume and linear charge densities
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<h3>What is volume?:</h3>

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The Volume of the rod is can be calculated using the formula below.

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<h3>What is linear charge density:</h3>

This is the ratio of the charge on an object to the length of the object.

The linear charge density of the rod can be calculated using the formula below.

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Where:

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  • Q = Charge on the rod.
  • h = height or length of the rod

From the question

Given:

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Substitute these values into equation 2

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Hence, The volume of the rod is 1.26×10⁻⁵ m³, and the linear charge density of the rod is 3.64 C/m

Learn more about charge density here: brainly.com/question/14568868

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