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vagabundo [1.1K]
2 years ago
9

Does anyone know the correct choice for this question? If its correct ill mark you as the best answer choice!

Mathematics
2 answers:
Rasek [7]2 years ago
8 0

Answer:

A) go to desmos.graphingcal for future help with graph questions.

Step-by-step explanation:

go to desmos online graphing cal and enter you points

enter the following:

f(x)=3x+4

(-1,1)

(0,4)

(1,7)

vitfil [10]2 years ago
6 0

Answer:

A

Step-by-step explanation:

The slope is positive. Also, using the rise/run method, I found that the slope is 3. The b is 4 because the line crosses the y axis at 4.

You might be interested in
Circles c and c are similar state the translation rule and the scale factor of dilation
IrinaVladis [17]

Answer:

To find the scale factor for a dilation, we find the center point of dilation and measure the distance from this center point to a point on the preimage and also the distance from the center point to a point on the image.

Step-by-step explanation:

5 0
2 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
The population of a rabbit colony triples each month.
djverab [1.8K]

Answer:

3645 rabbits after 6 months.

Step-by-step explanation:

The population of a rabbit colony triples each month.

This means that the population of the colony after t months is given by:

P(t) = P(0)(3)^t

In which P(0) is the initial population.

The population started with 5 rabbits.

This means that P(0) = 5

So

P(t) = 5(3)^t

How many rabbits are there after 6 months?

This is P(6). So

P(6) = 5(3)^6 = 3645

3645 rabbits after 6 months.

3 0
2 years ago
Determine if -10,-12,or -16is the solution of 2t-2=26
Dafna11 [192]
2t-2=26
first you would add 2 to both sides
that equals 2t=28
then you would divide both sides by two
that would give you
t= 14
3 0
3 years ago
What is the problem to this
irakobra [83]
4:9
24:x
Set up a proportion
4/9=24/x
4x=216
x=54
a) 54 is your answer
hope this helps, and please give brainliest if it does!
6 0
3 years ago
Read 2 more answers
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