Answer:
v₃ = 9.62[m/s]
Explanation:
To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.
We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.
Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.
In this way, we can construct the following equation.

where:
m₁ = mass of the astronaut = 157 [kg]
m₂ = mass of the toolkit = 5 [kg]
v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]
v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]
v₃ = velocity at which the toolkit should be thrown [m/s]
Now replacing:
![-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]](https://tex.z-dn.net/?f=-%28157%2B5%29%2A0.2%3D%28157%2A0.1%29-%285%2Av_%7B3%7D%29%5C%5C%285%2Av_%7B3%7D%29%3D%2015.7%2B32.4%5C%5Cv_%7B3%7D%3D9.62%5Bm%2Fs%5D)
Answer:2500kg
Explanation:
Weight of car(w)=25000N
Acceleration due to gravity approximately(g) 10m/s^2
Mass=w/g
Mass=25000/10
Mass=2500kg
Given:
500 containers ; 5 of these are defective.
A = event that 1st is defective = 5/500
B = event that 2nd is defective = 4/499
C = event that 3rd is defective = 3/498
a) 4/499
b) 5/500 * 4/499 = 20/249,500 = 1/12,475
c) 495/500 * 494/500 = 244,530 / 250,000 = 24,453/25,000
d) 5/500 * 4/499 * 3/498 = 60/124,251,000 = 1/2,070,850
B.
increases as the tension of the string increases
Answer:
<h2>11.6 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
mass is in kg
1000 g = 1 kg
145 g = 0.145 kg
From the question we have
force = 0.145 × 80
We have the final answer as
<h3>11.6 N</h3>
Hope this helps you