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photoshop1234 [79]
3 years ago
15

An astronaut and his space suit have a combined mass of 157 kg. The

Physics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

v₃ = 9.62[m/s]

Explanation:

To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.

We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.

Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.

In this way, we can construct the following equation.

-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})

where:

m₁ = mass of the astronaut = 157 [kg]

m₂ = mass of the toolkit = 5 [kg]

v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]

v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]

v₃ = velocity at which the toolkit should be thrown [m/s]

Now replacing:

-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]

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I would say D. because you round to the nearest whole number and 0.04 is way less than 0.5 which is a good rounding up number.
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A 57 kg boy and a 41 kg girl use an elastic rope while engaged in a tug-of-war on a frictionless icy surface. If the acceleratio
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Answer:

Acceleration of the boy a₁:

a_{1} = 1.87 \frac{m}{s^{2} }

Explanation:

Conceptual analysis

We apply Newton's second law to the boy and the girl:

F = m*a (Formula 1)

F : Force in Newtons (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Nomenclature

m₁ : boy mass

m₂ :  girl mass

a₁ : boy acceleration

a₂ :  girl acceleration

F₁ : boy acceleration

F₂ :  girl acceleration

Known data

m₁ =  57 kg

m₂ =  41  kg

a₂ = 2.6 m/s²

Problem development

We apply to Newton's third law of action and reaction, then:

F₁ = F₂ , We apply the formula (1):

m₁*a₁ = m₂*a₂

a_{1} = \frac{m_{2}* a_{2} }{m_{1} }

a_{1} = \frac{41* 2.6 }{ 57 }

a_{1} = 1.87 \frac{m}{s^{2} }

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