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3 years ago

An astronaut and his space suit have a combined mass of 157 kg. The

Physics

1 answer:

alexgriva [62]3 years ago

6 0

Answer:

v₃ = 9.62[m/s]

Explanation:

To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.

We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.

Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.

In this way, we can construct the following equation.

$-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})$

where:

m₁ = mass of the astronaut = 157 [kg]

m₂ = mass of the toolkit = 5 [kg]

v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]

v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]

v₃ = velocity at which the toolkit should be thrown [m/s]

Now replacing:

$-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]$

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A telephone pole has three cables pulling as shown from above, with F⃗ 1=(300.0iˆ+500.0jˆ) , F⃗ 2=−200.0iˆ , and F⃗ 3=−800.0jˆ .

Ray Of Light [21]

A) Net force in component form: $F=100.0i-300.0j$

B) Magnitude of the net force: 316.2, direction: $-71.6^{\circ}$

Explanation:

The three forces given in this problem are:

$F_1=300i+500j$

$F_2=-200i$

$F_3=-800 j$

The three forces are given in component form, where the components with unit vector i is the component along the x-direction, while the components with unit vector j is the component along the y-direction.

In order to find the net force in component form, we just need to add the components of the three forces along each direction. Therefore:

- Along the x-direction:

$F_x = F_{1x}+F_{2x}+F_{3x}=300+(-200)+0=100$

- Along the y-direction:

$F_y=F_{1y}+F_{2y}+F_{3y}=500+0+(-800)=-300$

So, the net force in component form is

$F=100.0i-300.0j$

The magnitude of a vector F is given by Pythagorean's theorem:

$|F|=\sqrt{F_x^2+F_y^2}$

where in this problem,

$F_x=100$ is the x-component

$F_y=-300$ is the y-component

Substituting,

$|F|=\sqrt{(100)^2+(-300)^2}=316.2$

The direction instead is given by

$\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{-300}{100})=-71.6^{\circ}$

where the negative sign means the direction is below the positive x-axis.

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

8 0

3 years ago

The half life of a species that undergoes zero order kinetics is ____ and the rate constant has units of ____.

-BARSIC- [3]

The reaction of the half-life is a description of the needed time for the reactant to deplete.In the first order reactions formula, k is considered as the first order rate constant whose unit is denoted as 1/s. Hope this helps.

6 0

4 years ago

A phone cord is 2.28 m long. The cord has a mass of 0.2 kg. A transverse wave pulse is produced by plucking one end of the taut

Debora [2.8K]

The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:

T = 10 N

The speed of a wave on a string is given by the relationship.

v = $\sqrt{\frac{T}{\mu } }$

Where v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

v = $\frac{d}{t}$

v = $\frac{4 L}{t}$

v = $\frac{4 \ 2.28 }{0.849}$

v = 10.7 m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

μ = $\frac{m}{L}$

$\mu = \frac{0.2}{2.28}$

μ = 8.77 10⁻² kg / m

The tension is:

T = v² μ

Let's calculate

T = 10.7² 8.77 10⁻²

T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

T = 10 N

Learn more here: brainly.com/question/12545155

7 0

3 years ago

Because electricity and magnetism are so closely related, factors that affect one often affect the other.

xenn [34]

Answer:

The interactions of electricity and magnetism are difficult to explain in nontechnical terms. This is primarily because one has to describe the interactions in terms of invisible "force fields" which shift, expand, contract, strengthen, weaken, and rotate in space, and these are very difficult to describe adequately in verbal terms. In mathematical terms, coupled sets of three-dimensional vector differential equations are required, and these are also quite difficult to visualize.

Explanation:

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3 years ago

Density Questions

Katen [24]

Explanation:

let's take the volume of each first:

ice cream: 10×10×4=400cm^3

freezer: 40×40×20=32,000cm^3

now we just divide: 32000/400=80

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3 years ago