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photoshop1234 [79]
3 years ago
15

An astronaut and his space suit have a combined mass of 157 kg. The

Physics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

v₃ = 9.62[m/s]

Explanation:

To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.

We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.

Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.

In this way, we can construct the following equation.

-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})

where:

m₁ = mass of the astronaut = 157 [kg]

m₂ = mass of the toolkit = 5 [kg]

v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]

v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]

v₃ = velocity at which the toolkit should be thrown [m/s]

Now replacing:

-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]

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A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
LUCKY_DIMON [66]

Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

Mass of the person  standing on platform = 65.7 kg

Distance from the center of platform = 1.07 m

Mass of the dog on the platform = 27.3 kg

Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = \frac{MR^2}{2}

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia (I_y_y )  of the system with respect to the axis yy.

⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

⇒ I_y_y=289.088\ kg.m^2

The moment of inertia of the system is 289.088 kg.m^2

7 0
3 years ago
Which of the following ranching practices contributes to soil erosion?
Natasha2012 [34]

A. overgrazing of livestock

Explanation:

Overgrazing of livestock is the ranch practice that contributes to soil erosion.

Soil erosion is the washing away of the top layer of the earth on which plant grows.

  • Plants are covers of the earth and they prevent agents of denudation from actively washing away the soil.
  • When livestock are introduced into a place, continuous grazing leaves the surface bare.
  • The plants becomes depleted and the surface is exposed.
  • This fast tracks the process of overgrazing.

learn more:

Soil erosion brainly.com/question/2473244

#learnwithBrainly

6 0
3 years ago
HELP ASAPPP PLZZZ I HAVE A TIMER WILL GIVE YOU THE 30 POINTS
trapecia [35]
It holds the atoms together (aka your last option)
8 0
3 years ago
Bonsoir, je suis complètement bloquée, j’ai besoin de répondre aux 3 questions:
Lapatulllka [165]

Answer:

3)le changement oblige le monde à rechercher des sources d'énergie et de carburant alternatives à faible émission de carbone.... le remplacement des combustibles fossiles par des alternatives renouvelables telles que les biocarburants est un moyen efficace de réduire ces émissions ... ... combiné à une croissance économique significative dans les économies émergentes ... 3) Sécuriser l'approvisionnement énergétique

Explanation:2)Le calculateur d'équivalences de gaz à effet de serre utilise le taux d'émission marginal moyen pondéré national américain de CO2 moyen de l'outil AVoided Emissions and GenRation Tool (AVERT) pour convertir les réductions de kilowattheures en unités évitées d'émissions de dioxyde de carbone.

La plupart des utilisateurs du calculateur d'équivalences qui recherchent des équivalences pour les émissions liées à l'électricité veulent connaître les équivalences pour les réductions d'émissions des programmes d'efficacité énergétique (EE) ou d'énergie renouvelable (ER). Pour calculer les effets des émissions d'EE et d'ER sur le réseau électrique, il faut estimer la quantité de production d'énergie fossile et les émissions déplacées par l'EE et les ER. Un facteur d'émission marginal est la meilleure représentation pour estimer quelles unités alimentées aux combustibles fossiles EE / ER sont déplacées dans le parc fossile. Les programmes d'EE et d'ER ne sont généralement pas supposés affecter les centrales électriques de base qui fonctionnent tout le temps, mais plutôt les centrales électriques marginales qui sont mises en service si nécessaire pour répondre à la demande. Par conséquent, AVERT fournit un facteur d'émission marginal national pour le calculateur d'équivalences.

Facteur d'émission

1558,8 lb CO2 / MWh × (4,536 × 10-4 tonnes métriques / lb) × 0,001 MWh / kWh = 7,07 × 10-4 tonnes métriques CO2 / kWh

1)Dans le préambule de la réglementation conjointe EPA / Department of Transportation du 7 mai 2010 qui a établi les normes d'économie de carburant du programme national initial pour les années modèles 2012-2016, les agences ont déclaré qu'elles avaient accepté d'utiliser un facteur de conversion commun de 8887 grammes de Émissions de CO2 par gallon d'essence consommé (Federal Register 2010). A titre de référence, pour obtenir le nombre de grammes de CO2 émis par gallon d'essence brûlée, la teneur en chaleur du carburant par gallon peut être multipliée par le kg de CO2 par teneur en chaleur du carburant.

Cette valeur suppose que tout le carbone de l'essence est converti en CO2 (GIEC 2006).

Calcul

8887 grammes de CO2 / gallon d'essence = 8,887 × 10-3 tonnes métriques de CO2 / gallon d'essence

7 0
3 years ago
An ultrasound wave vibrates 30,000 times per second. what is the frequency
erica [24]
Frequency is given in units of Hertz (Hz) and is defined as the number of cycles per second.  The sound wave has 30,000 cycles per second, so its frequency is 30,000Hz.
This is more conveniently expressed as 30kHz, where the k indicates a multiplier of 1,000.
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