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Ilya [14]
3 years ago
13

Do energy drinks actually provide energy?

Physics
2 answers:
denis-greek [22]3 years ago
6 0

Answer:

Most energy drinks contain large amounts of caffeine, which can provide a temporary energy boost. Some energy drinks contain sugar and other substances. The boost is short-lived, however, and may be accompanied by other problems.

Explanation:

Phoenix [80]3 years ago
4 0

Answer:

kinda

Explanation:

Most energy drinks contain large amounts of caffeine, which can provide a temporary energy boost. Some energy drinks contain sugar and other substances. The boost is short-lived, however, and may be accompanied by other problems.

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Help me with the question b.​
Morgarella [4.7K]

Answer:

a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.

b) Liquid P - Q = 3840\,J, Liquid Q - Q = 5500\,J, Liquid R - Q = 7800\,J, Liquid S - Q = 2856\,J

Explanation:

a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.

b) Let suppose that heat transfer rates between liquids and surroundings are stable. The quantity of the heat released is determined by the following expression:

Q = m\cdot c\cdot (T_{r} - T_{f}) (1)

Where:

m - Mass of the liquid, in kilograms.

c - Specific heat capacity, in joules per kilogram-degree Celsius.

T_{r} - Initial temperature of the sample, in degrees Celsius.

T_{f} - Freezing point, in degrees Celsius.

Liquid P (m = 1\,kg, c = 160\,\frac{J}{kg\cdot ^{\circ}C}, T_{r} = 30\,^{\circ}C, T_{f} = 6\,^{\circ}C)

Q = (1\,kg)\cdot \left(160\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 6\,^{\circ}C)

Q = 3840\,J

Liquid Q (m = 1\,kg, c = 220\,\frac{J}{kg\cdot ^{\circ}C}, T_{r} = 30\,^{\circ}C, T_{f} = 5\,^{\circ}C)

Q = (1\,kg)\cdot \left(220\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 5\,^{\circ}C)

Q = 5500\,J

Liquid R (m = 1\,kg, c = 300\,\frac{J}{kg\cdot ^{\circ}C}, T_{r} = 30\,^{\circ}C, T_{f} = 4\,^{\circ}C)

Q = (1\,kg)\cdot \left(300\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 4\,^{\circ}C)

Q = 7800\,J

Liquid S (m = 1\,kg, c = 102\,\frac{J}{kg\cdot ^{\circ}C}, T_{r} = 30\,^{\circ}C, T_{f} = 2\,^{\circ}C)

Q = (1\,kg)\cdot \left(102\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 2\,^{\circ}C)

Q = 2856\,J

6 0
3 years ago
A wire is hung between two towers and has a length of 208 m. A current of 154 A exists in the wire, and the potential difference
NARA [144]

Answer:

Mass = 4152kg

Explanation:

Given

L = 208m

I = 154A

V = 0.245V

Density = 3610 kg/m3

ρ = 4.23 x 10-8Ω·m = resistivity of wire

Resistance R = ρL/ A

R = voltage / current = V/I = 0.245/154 = 1.59×10-³ohms

1.59×10-³ = 4.23 x 10-⁸×208/A

Rearranging,

A = 4.23 x 10-⁸×208/1.59×10-³

A = 5.53×10-³m²

Mass = density × volume

Volume = L×A = 208×5.53×10-³m³= 1.15m³

Mass = 3610×1.15 = 4152kg

5 0
3 years ago
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<span>from a trough to the rest position and from a crest to the rest position.

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3 0
4 years ago
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Answer:

A. transverse waves

vote me brainliest?? 5/5

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3 years ago
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What are the Rules of magnetism
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all the allials must be aligned in the same direction

magnets are affected by heat, drops, and improper storage

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3 years ago
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