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murzikaleks [220]
3 years ago
6

How do you calculate the electric force by object a exerted on object a (itself)?

Physics
1 answer:
max2010maxim [7]3 years ago
5 0

I don't think an object can exert a force on itself.

Try it: Get up on a skateboard, and see if you can do anything to yourself that makes you start moving ... without touching anything else.

It'll be easy to tell if you succeed. If you actually do exert an unbalanced force on yourself, then you'll begin to accelerate.

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6x10^8 kg<br> —————<br> 2x10^4 m^3
barxatty [35]
The answer to the question

4 0
4 years ago
A delivery truck travels 2.8 km North, 1.0 km East, and 1.6 km South. The final displacement from the origin is ___km to the ___
34kurt

Answer:

The final displacement from the origin is <u>1.6</u> km to the <u>NE</u>

Explanation:

The directions in which the delivery truck travels are;

1) 2.8 km North = 2.8·\hat j, in vector form

2) 1.0 km East = 1.0·\hat i, in vector form

3) 1.6 km South = -1.6·\hat j, in vector form

Therefore, to find the final displacement, Δx, of the delivery truck, we add the individual displacements as follows;

Final displacement, Δd = 2.8·\hat j + 1.0·\hat i +(-1.6·\hat j) = 1.2·\hat j + 1.0·\hat i

Final displacement, = 1.0·\hat i + 1.2·\hat j

Where;

Δx = The displacement in the x-direction = 1.0·\hat i

Δy = The displacement in the y-direction = 1.2·\hat j

The magnitude of the resultant displacement vector is given as follows

\left | d \right | = √((Δx)² + (Δy)²) = √(1² + 1.2²) ≈ 1.6 (To the nearest tenth)

The magnitude of the resultant displacement vector ≈ 1.6 km

The direction of the resultant vector is positive for both the east and north direction, therefore, the direction of the resultant vector = NE

Therefore, the resultant displacement of the delivery truck is approximately 1.6 km, NE from the origin.

3 0
3 years ago
The specific heat of granite is 800 J/(kg·°C). How much heat does it take to raise 1 kg of granite 4°C?
Triss [41]
Q=mcΔt
Q= 1kg * 800J/kg°C*4°C
Q= 3200J
7 0
3 years ago
The electric field strength in the space between two closely spaced parallel disks is 1.0 105 N/C. This field is the result of t
balu736 [363]

Answer:

D=2.996\times 10^{-2} m

Explanation:

*Assume the parallel disks have equal diameters.

Given the electric strength as  1.0\times 10^5 N/C.  transferring 3.9\times 10^9 electrons, the disk's Area can be calculated using the formula:

E=\frac{\eta}{\epsilon_o}=\frac{Q}{A\epsilon_o}\\\\A=\frac{Q}{E\epsilon_o}\\\\=\frac{(3.9\times 10^9)\times (1.6\times10^{-19})}{(1.0\times 10^5 )\times (8.85\times10^{-12})}\\\\A=7.0508\times 10^{-4} \ m^2

#We now calculate the disks diameter:

A=\pi(D/2)^2\\\\2\sqrt{\frac{A}{\pi}}=D\\\\=2\sqrt{7.0508\times 10^{-4}/\pi}\\\\D=2.996\times 10^{-2} \ m

Hence, the diameter of the disks is D=2.996\times 10^{-2} m

8 0
3 years ago
What are 3 subatomic particles of an atom?
Vesnalui [34]
Protons, neutrons, and electrons<span> are the three main subatomic particles found in an atom.</span>
7 0
3 years ago
Read 2 more answers
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