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bagirrra123 [75]
3 years ago
11

A car manufacturer wants to change its car’s design to increase the car’s acceleration. Which changes should the engineers consi

der making to the design?
Physics
1 answer:
likoan [24]3 years ago
4 0

Answer:

The car manufacturers could increase bore of the cylinders, place the engine in the center or back of the car, add 1 to 2 turbochargers, and lower the center of gravity of the vehicle to increase traction.

Explanation:

Turbochargers would be recommended because they significantly increase both the torque of the engine as well as the amount of horses powering the car while also increasing original efficiency both with and without the additional power. Weight adjustment allows for lightweight vehicles with good traction. This is important to both keep control of the car under acceleration, but it also makes the vehicle more efficient due to the now sheddable unnecessary weight. A more obvious approach would be to increase the base horsepower and torque of the engine by increasing the bore of the cylinders and the weight of the pistons. This acts as an inertial lever, because the extra piston weight will drag the crankshaft faster. This could also be achieved by taking away piston weight, but this could be catastrophic should a piston slip.

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Answer:

Your answer will be 6.0kg•m/s

Explanation:

In the given question all the required details d given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.We know the equation of finding momentum asMomentum = mass * velocity                   = 5 * 1.2                    = 6So the momentum of the object is 6 Newton.

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3 years ago
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What does the term conserved mean?
Morgarella [4.7K]
There’s many terms to it

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2 years ago
Consider two antennas separated by 9.00 m that radiate in phase at 120 MHz, as described in Exercise 35.3. A receiver placed 150
alexgriva [62]

Answer:

\phi=4.52 rad

Explanation:

From the question we are told that

Distance b/e antenna's d=9.00m

Frequency of antenna RadiationF_r=120 MHz \approx 120*10^6Hz

Distance from receiver d_r=150m

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Distance difference of the receiver b/w antenna's (r^2-r^1)=1.8m

Generally the equation for Phase difference \phi is mathematically given by

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 \phi=\frac{2*\pi}{\frac{3*10^{8}}{120*10^6}} *1.8

 \phi=\frac{4\pi}{5}  *1.8

<h3>  \phi=4.52 rad</h3>

Therefore phase difference f between the two radio waves produced by this path difference is given as

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7 0
2 years ago
which has a higher acceleration:a 10kg object acted upon with a net force of 20N or an 18kg object acted on by a net force of 20
MA_775_DIABLO [31]
<span>Answer: The acceleration of 10 kg object is greater than that of 18 kg object.

Explanation:
According to Newton's Second law:
F = ma --- (A)

Let's find the acceleration for both 10 kg and 18 kg objects!
The net force on both of these masses = F = 20N

(1) Acceleration of 10 kg object
Mass = m = 10 kg
Plug in the values in equation (A):
20 = 10 * a
Acceleration = a = 2 m/s^2

(2) Acceleration of 18 kg object
Mass = m = 18 kg
Plug in the values in equation (A):

20 = 18 * a
Acceleration = a = 1.11 m/s^2


2 > 1.11; therefore, 10 kg object has the higher acceleration compared to the acceleration of the 18 kg object.</span>
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Motion is a change in direction. True or False?
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False... motion is a change in position. Not direction
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