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bagirrra123 [75]
3 years ago
11

A car manufacturer wants to change its car’s design to increase the car’s acceleration. Which changes should the engineers consi

der making to the design?
Physics
1 answer:
likoan [24]3 years ago
4 0

Answer:

The car manufacturers could increase bore of the cylinders, place the engine in the center or back of the car, add 1 to 2 turbochargers, and lower the center of gravity of the vehicle to increase traction.

Explanation:

Turbochargers would be recommended because they significantly increase both the torque of the engine as well as the amount of horses powering the car while also increasing original efficiency both with and without the additional power. Weight adjustment allows for lightweight vehicles with good traction. This is important to both keep control of the car under acceleration, but it also makes the vehicle more efficient due to the now sheddable unnecessary weight. A more obvious approach would be to increase the base horsepower and torque of the engine by increasing the bore of the cylinders and the weight of the pistons. This acts as an inertial lever, because the extra piston weight will drag the crankshaft faster. This could also be achieved by taking away piston weight, but this could be catastrophic should a piston slip.

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Stand on a bathroom scale on a level floor, and the reading on the scale shows the gravitational force on you, mg. If the floor
kari74 [83]

Answer:

<em>The angle introduces an error on the mesure of the weight</em>

Explanation:

<u><em>Weight and Normal Forces</em></u>

When an object is resting on a horizontal surface, its weight is directed downwards and the normal force has the same magnitude and opposite direction, i.e. directed upwards. When some angle α exists between the surface and the horizontal plane, the scale keeps 'feeling' the Normal force, but it's not equal to the weight anymore, but to the perpendicular component of the weight to the surface where the scale is placed. It can be found that the component of the weight is m.g.cosα

If, for example \alpha=10^o, the real measure is

m.g.cos 10^o=0.985(mg)

That is, 98.5% of the correct weight. So it's important to measure weight on horizontal surfaces

7 0
3 years ago
A 6.0-cm-diameter horizontal pipe gradually narrows to 4.5 cm. When water flows through this pipe at a certain rate, the gauge p
Rufina [12.5K]

Answer:

0.0072 m³/s

Explanation:

Using Bernoulli's law

P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂ since the pipe is horizontal

1/2ρv₂² - 1/2ρv₁² = P₁ - P₂

flow rate is constant

A₁v₁ = A₂v₂

A₁ = πr₁² = π (0.06/2)² = 0.0028278 m²

A₂ = πr₂² = π (0.0225)² = 0.00159 m²

v₁  = (A₂ / A₁)v₂

v₁  = (0.00159 m²/ 0.0028278  m²) v₂ = 0.562  v₂

substitute v₁  into the Bernoulli's equation

1/2ρv₂² - 1/2ρv₁² = P₁ - P₂

500 ( 1 - 0.3161 ) v₂²  = (31.0 - 24 ) × 10³ Pa

341.924 v₂² = 7000

v₂² = 20.472

v₂ = √ 20.472 = 4.525 m/s

volume follow rate = 0.00159 m² ×  4.525 m/s = 0.0072 m³/s

8 0
3 years ago
Which of the following illustrates two resistors in a parallel circuit
IRINA_888 [86]

In option A there are two resistors in which two terminals of resistors are connected with the terminals of battery so here they are connected in parallel.

In option B all resistors and battery is connected in a single loop so it is a series combination of all.

In option C all three resistors are connected by their terminals to a single battery so here all three resistor are in parallel with the battery.

In option D only one resistor is connected in series with a battery as one single loop is there.

So in the above all cases two resistors are in parallel with battery in option A

8 0
3 years ago
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Why do you see colors when you look at reflected light from a cd
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The colors that you see on the CD are created by white light reflecting from ridges in the metal. When light reflects off or passes through something with many small ridges or scratches, you often get rainbow colors and interesting patterns. They are called interference patterns.
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8 0
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