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lukranit [14]
2 years ago
9

Dr. Glover's office has one vendor for their practice management software and another for their electronic health record, but th

e systems are able to communicate with one another without duplicating data entry. The systems are able to
Physics
1 answer:
Sliva [168]2 years ago
5 0

Answer:

Interface

Explanation:

This is a classic example of Interface technology.

An interface allows different software packages to communicate without re-entering data.

Here in this case also systems are able to communicate with one another without duplicating data entry. For example, practice management software and another for their electronic health record.

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Which percentage best describes the visibility of a waxing crescent moon
Rus_ich [418]

Answer:

It be 0,1% - 49.9%

This is because the new moon is 0.0% and the first quarter is 50%.

3 0
2 years ago
At a point 1.2 m out from the hinge, 14.0 N force is exerted at an angle of 27 degrees to the moment arm in a plane which is per
geniusboy [140]

Answer:

\tau = 7.63 Nm

Explanation:

As we know that moment of force is given as

\tau = \vec r \times \vec F

now we have

\vec r = 1.2 m

\vec F = 14 N

now from above formula we have

\tau = r F sin\theta

here we know that

\theta = 27 degree

so we have

\tau = (1.2)(14) sin27

\tau = 7.63 Nm

3 0
2 years ago
A rectangular block of copper metal weighs 1896 g. The dimensions of the block are 8.4 cm by 5.5 cm by 4.6 cm. From this data, w
sp2606 [1]

Answer:

8.9 g/cm^3

Explanation:

density = mass/volume

volume = length * width * height

volume = (8.4 cm)(5.5 cm)(4.6 cm)

volume = 212.52 cm^3

mass = 1896 g

density = (1896 g)/(212.52 cm^3)

density = 8.9 g/cm^3

3 0
3 years ago
A mass of 5 kg of saturated water vapor at 150 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate
yulyashka [42]

Answer:

The work done by the steam is 213 kJ.

Explanation:

Given that,

Mass = 5 kg

Pressure = 150 kPa

Temperature = 200°C

We need to calculate the specific volume

Using formula of work done

W=Pm\DeltaV

W=Pm(\dfrac{RT_{1}}{P_{atm}}-\dfrac{RT_{2}}{P_{atm}}

W=\dfrac{PmR}{P_{atm}}(T_{2}-T_{1})

Where,R = gas constant

T = temperature

P = pressure

P_{atm}=Atmosphere pressure

m = mass

Put the value into the formula

W=\dfrac{150\times10^{3}\times5\times287.05}{1.01\times10^{5}}\times(473-373)

W=213\ kJ

Hence, The work done by the steam is 213 kJ.    

6 0
3 years ago
____ crust forms the ocean floors
Fittoniya [83]

Answer:

lithosphere

Explanation:

6 0
3 years ago
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