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3 years ago

Hi

2 answers:

8 0

Endoskeleton- an internal skeleton, such as the bony or cartilaginous skeleton of vertebrates.

Exoskeleton- a rigid external covering for the body in some invertebrates animals, especially Arthropods, providing both support and protection.

shutvik [7]3 years ago

6 0

Answer:

An endoskeleton is formed on the inside of an animal's body, while an exoskeleton is formed on the outside of an animal's body. ... An endoskeleton can support a large body size and is often made of bone. An exoskeleton cannot support a large body size and is often made of chitin or minerals.

Explanation:

endoskeleton - It is an internal skeleton present inside the body of a living organism, e.g. a bony or a cartilaginous skeleton of vertebrates.

exoskeleton - The endoskeleton mainly comprises bones and cartilage

PLS MARK BRAINLIEST!

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A 2-lb slider is propelled upward at A along the fixed curved bar which lies in a vertical plane. If the slider is observed to h

timofeeve [1]

To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.

PART A) Normal Force.

$F_n = \frac{mv^2}{r}$

$N+mgcos\theta = \frac{mv^2}{r}$

Here,

Normal reaction of the ring is N and velocity of the ring is v

$N+mgcos\theta = \frac{mv^2}{r}$

$N+Wcos\theta = \frac{W}{g} (\frac{v^2}{r})$

$N+2cos30\° = \frac{2}{32.2}*\frac{10^2}{2}$

$N = 1.374lb$

PART B) Acceleration

$F_t = ma_t$

$-mgsin\theta = ma_t$

$-W sin\theta = \frac{W}{g} a_t$

$-2Sin30\° = (\frac{2}{32.2})a_t$

$a_T = -16.10ft/s^2$

Negative symbol indicates deceleration.

<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>

8 0

3 years ago

A ball rolls with a speed of 2.0m/s across a level table that is 1.0m above the floor. Upon reaching the edge of the table it fo

Mekhanik [1.2K]

Answer:0.58 m

Explanation:

The initial velocity of the ball is u = 2.0 m/s

The height of the table is, h = 1.0 m

The ball falls in vertical direction under acceleration due to gravity.

Time taken for ball to hit the floor:

h= ut + 0.5gt² ( from the equation of motion)

1.0 m=2.0 m/s × t+0.5 × 9.8 m/s²× t²

Solving this for t,

t = 0.29 s ( we have neglected the negative value of t)

In the same time, the ball would cover a horizontal distance of :

s = u t

⇒s = 2.0 m/s×0.29 s = 0.58 m

Thus, the landing spot is 0.58 m away from the table.

6 0

3 years ago

Read 2 more answers

Where are electrons located in an atom?

Scilla [17]

Answer:

B. Outside the nucleus.

Explanation:

Electrons orbit the nucleus of the atom.

7 0

1 year ago

What is the minimum diameter necessary for a radio telescope working at f=1×10^10 Hz to be able to separate two objects 1 deg ap

Ad libitum [116K]

Your answer is a yessssssir

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2 years ago

Two blocks with different temperatures had entropies of 10 J/K and 30 J/K before they were brought in contact. What can you say

True [87]

Answer:

a. Ssystem > 40 J/K

Explanation:

Given that

The entropy of first block = 10 J/K

The entropy of second block = 30 J/K

When two bodies come into contact with each other, the entropy of the combined system will increase and the entropy sum remains unchanged: According to the Second law of thermodynamics.The entropy of the system will be greater than 40 J/K.

Therefore the answer is a.

Ssystem > 40 J/K

6 0

2 years ago