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wariber [46]
3 years ago
9

Sodium is going in group 1, period 3. It contains A. One valence electron in its 3rd energy shell B three valence electron in it

s 1st energy shell C. 11 protons, 11electrons , 11 neutrons D. 11 protons, 11 electrons and 23 neutrons
Chemistry
1 answer:
topjm [15]3 years ago
5 0

Answer:

The correct answer is option A, that is, one valence electron in its third energy shell and option C, that is, 11 electrons and 11 protons.

Explanation:

The outermost electrons and the ones that take part in the process of bonding are termed as valence electrons. The atomic number of sodium is 11, thus, it possesses 11 protons and the atoms are neutral so it suggests that sodium has 11 electrons. By electronic configuration, it can be seen that in sodium, two electrons are present in the first shell, 8 in the second, and only one electron in the third shell, that is, 2.8.1. The electron present in the third shell is the valence electron.

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A sample of nitrous Oxide has a volume of 1 £.20 at 1500 mm HG and -10°C. Calculators pressure when it’s value is compressed 250
ExtremeBDS [4]

Answer:

nitric acid will be if you get you will pixel purpose

3 0
3 years ago
Please help fast...please
RSB [31]

Answer:

Radioactive

Explanation:

hope this helped! :)

5 0
3 years ago
If the formation of NaCl proceeds according to the following equation and change in enthalpy, what is the reaction and change in
Sergio039 [100]

Answer:

  • <em>2NaCl → 2Na + Cl₂, ΔH = 822 kJ </em>

Explanation:

The chemical <em>equation</em> for the <em>formation of NaCl</em> is:

  • Na + (1/2) Cl₂ → NaCl , ΔH = - 411 kJ

That equation means that 1 mole of NaCl is formed by the reaction of 1 mole of Na and 1/2 mole of Cl₂, with a release of energy of 411 kJ.

The <em>decomposition</em> of <em>NaCl</em> is the inverse of the <em>formation</em> reaction; thus, you swift products and reactants and inverse the sign of the <em>change in enthalpy:</em>

  • NaCl → Na + 1/2 Cl₂, ΔH = 411 kJ

Since you want the decomposition of 2 moles you multiply the equation and the ΔH by 2:

  • 2NaCl → 2Na + Cl₂, ΔH = 822 kJ ← answer

3 0
3 years ago
What is the oxidation number of a group 1a compoubds?
SVETLANKA909090 [29]

Answer:-

+1

Explanation:-

Group 1 A compounds has 1 valence electron.

According to the octet rule, if outermost shell has 8 electrons then it is stable.

So Group 1 A compounds lose 1 electron to fulfill octet.

Oxidation number is the number of electrons lost or gained. It is positive if electrons are lost and negative if electrons are gained.

Hence the oxidation number of group 1 A compounds is +1.

7 0
3 years ago
an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m
bogdanovich [222]

Answer:

P_2=1.1x10^6Pa

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

P_1V_1=P_2V_2

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

P_2=\frac{P_1V_1}{V_2}

Consider that the given initial pressure is also equal to Pa:

P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa

Which stands for a pressure increase when volume decreases.

Regards.

4 0
3 years ago
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