Answer:it is sterilized in the process
Explanation:
There will be 7.5 g of Be-11 remaining after 28 s.
If 14 s = 1 half-life, 28 s = 2 half-lives.
After the first half-life, ½ of the Be-11 (15 g) will disappear, and 15 g will remain.
After the second half-life, ½ of the 15 g (7.5 g) will disappear, and 7.5 g will remain.
In symbols,
<em>N</em> = <em>N</em>₀(½)^<em>n</em>
where
<em>n</em> = the number of half-lives
<em>N</em>₀ = the original amount
<em>N</em> = the amount remaining after <em>n</em> half-lives
Electron affinity corresponds to the energy released when an electron is added to<span> a </span>neutral atom in the gas phase<span>.
hope this helps!</span>
Answer:
4.62
so 5
the ratio is 2 na chlorates for 3 O2 so multiply 7 by 2/3
Explanation:
