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wariber [46]
3 years ago
9

Sodium is going in group 1, period 3. It contains A. One valence electron in its 3rd energy shell B three valence electron in it

s 1st energy shell C. 11 protons, 11electrons , 11 neutrons D. 11 protons, 11 electrons and 23 neutrons
Chemistry
1 answer:
topjm [15]3 years ago
5 0

Answer:

The correct answer is option A, that is, one valence electron in its third energy shell and option C, that is, 11 electrons and 11 protons.

Explanation:

The outermost electrons and the ones that take part in the process of bonding are termed as valence electrons. The atomic number of sodium is 11, thus, it possesses 11 protons and the atoms are neutral so it suggests that sodium has 11 electrons. By electronic configuration, it can be seen that in sodium, two electrons are present in the first shell, 8 in the second, and only one electron in the third shell, that is, 2.8.1. The electron present in the third shell is the valence electron.

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A gaseous hydrogen and carbon containing compound is decomposed and formed to contain 82.66% carbon and 17.34% hydrogen by mass.
Romashka [77]

Explanation:

Mole percentage of carbon = \frac{percentage given}{molar mass of carbon}

                                              = \frac{82.66}{12}

                                              = 6.89

Mole percentage of hydrogen = \frac{percentage given}{molar mass of hydrogen}

                                               = \frac{17.34}{1}

                                               = 17.34

Now, dividing mole percentage of both the atoms by 6.89.

Then,     C = 1 and H = \frac{17.34}{6.89} = 2.5

Hence, empirical formula is C_{2}H_{5}.

As, it is given that P = 556 mm Hg. Convert mm Hg into atm as follows.

                        \frac{556 mm Hg \times atm}{760 mm Hg}

                             = 0.7316 atm

Volume is given as 158 mL. So, in liter volume is \frac{158}{1000} equals 0.158 L.

According to ideal gas equation, PV = nRT

                      0.7316 atm \times 0.158 L = \frac{mass}{molar mass} \times 0.082 atm L/mol K \times 298 K          

                       0.7316 atm \times 0.158 L = \frac{0.275 g}{molar mass} \times 0.082 atm L/mol K \times 298 K        

                   molar mass = 58.2 g

Hence, molecular weight of C_{2}H_{5} is 12 \times 2 + 5 = 29.

Therefore, (C_{2}H_{5})_{n} = 58

                               29 × n = 58

                                   n = 2

Thus, molecular formula of the compound is C_{4}H_{10}.

8 0
4 years ago
What volume (mL) of 7.48x10 -2 M phosphoric acid can be completely reacted with 115 mL of .244 M sodium
Y_Kistochka [10]

Answer:125ml - volume of phosphoic acid

Explanation:

The equation of the reaction is

H3PO4 + 3 NaOH ---> Na3PO4 + 3H2O

Such that I mole of H3PO4 reacts with 3 moles of  NaOH to produce the products above.

Given that

M1= Molarity of phosphoric acid = 7.48x10^-2 M

n1= number of moles of phosphoric acid = 1

V1=? ml

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V2= volume of sodium hydroxide= 115ml

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Using the Dilution equation formulae,

M1V1/n1 = M2V2/n2

7.48X10-2 x V1 /1= 0.244M x 115ml/3

V1=0.244Mx115mlx1/0.0748M X 3

V1= 28.06/0.2244= 125.04ml

V1=125.04ml rounded up to 125ml

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