You need 158.70 grams of Fe2O3 to produce 111 grams of Fe. This is calculated by using the molar masses and stoichiometric relationship of the two compounds.
Solution:
MM Fe = 55.845 g/mol
MM Fe2O3 = 159.69 g/mol
Fe: Fe2O3 = 2 mol:1 mol
11 g FE (1 mol Fe/55.845 g Fe) (1 mol Fe2O3/2 mol Fe) (159.69 g Fe2O3 / 1 mole Fe2O3) = 158.70 grams Fe2O3
The process of uranium mining generates what is called uranium tailings. These are the waste by products of uranium mining. Tailings contain the radioactive decay products of the uranium atom and these products are quite radioactive. Radioactive particles found in tailings can emit anywhere from twenty to one hundred times as much radiation as the natural levels at natural uranium deposits. These radioactive byproducts can lead to cancer if exposed.
White tern catches fish including crustaceans, flying fish, squid, and others. Prior of plunging into water, it hovers initially over the water surface and then either dives or dips in the surface, without getting entirely submerged into water, and catches its target.
The food or fish is captivated in its small, however, sharp black beak that is specific as it bent upwards and tapers to a sharp point. It also possesses a long slender body with tapering, long wings, all of which encourage its diving or dipping activity into the surface of the water.
The solution for this problem is:
Look for the moles of NaOH which is 0.0385 L x 0.150 M = 0.00578
H3PO4 + 3 NaOH = Na3PO4 + 3 H2O
moles H3PO4 = 0.00578 / 3 = 0.00193
M of H3PO4 = 0.00193 mol / 0.0150 L= 0.128 is the molality we are looking for in this problem.
