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klio [65]
2 years ago
7

A sample of seawater consists of water, sodium ions, chloride ions, and several other dissolved salts. These ions and salts are

evenly distributed throughout the water.
Which term or terms could be used to describe this sample of seawater?
a. Mixture
b. Heterogeneous mixture
c. Homogeneous mixture
d. Solution
e. Pure chemical substance
f. Compound
g. Element
Chemistry
1 answer:
wolverine [178]2 years ago
4 0

Answer:

The correct option is c

Explanation:

An homogeneous mixture is a mixture (either solid, liquid or gas) in which the constituents of the mixture are evenly distributed. Examples are pure sample of air, salt solution and sugar solution. Homogeneous mixture can be explained from the example given in the question; if 5 ml sample of a sea water is collected, the quantity of water, sodium ions, chloride ions and other dissolved salts will be equal in each 1 ml of the sample. This means the water, ions and salts are equally distributed.

When they are not equally distributed, it is known as heterogeneous mixture. Generally, a mixture is a combination of two or more substances that are not chemically combined or are physically combined.

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maks197457 [2]

<u>Answer:</u> The mass of H_2O produced is 2.52 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For hexane:</u>

Given mass of hexane = 1.72 g

Molar mass of hexane = 86.18 g/mol

Putting values in equation 1, we get:

\text{Moles of hexane}=\frac{1.72g}{86.18g/mol}=0.020mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 8.0 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{8.0g}{32g/mol}=0.25mol

The chemical equation for the combustion of hexane follows:

2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O

By stoichiometry of the reaction:

If 2 moles of hexane reacts with 19 moles of oxygen gas

So, 0.020 moles of hexane will react with = \frac{19}{2}\times 0.020=0.19mol of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, hexane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of hexane produces 14 moles of H_2O

So, 0.020 moles of hexane will produce = \frac{14}{2}\times 0.020=0.14mol of H_2O

We know, molar mass of H_2O = 18 g/mol

Putting values in above equation, we get:

\text{Mass of }H_2O=(0.14mol\times 18g/mol)=2.52g

Hence, the mass of H_2O produced is 2.52 g

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