Answer:
The lower confidence limit of the 95% confidence interval for the population proportion of Americans who were victims of identity theft is 0.0275.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
A 2003 survey showed that 14 out of 250 Americans surveyed had suffered some kind of identity theft in the past 12 months.
This means that 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The lower confidence limit of the 95% confidence interval for the population proportion of Americans who were victims of identity theft is 0.0275.
Answer:
50% of 108: 54
25% of 108: 27
75% of 108: 81
Step-by-step explanation:
Hope this helps have a nice day
I = prt
t = I/pr = 105/(700 x 0.05) = 105/35 = 3
Therefore, t = 3.
Answer:
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Answer:
x = -8/29 = -0.276
Step-by-step explanation:
Step 1 :
Solving a Single Variable Equation :
1.1 Solve : 29x+8 = 0
Subtract 8 from both sides of the equation :
29x = -8
Divide both sides of the equation by 29:
x = -8/29 = -0.276
One solution was found :
x = -8/29 = -0.276
Processing ends successfully
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