The final temperature of the mixture in the coffee cup calorimeter is; 19.467 °C
According to the law of energy conservation:
As such; the heat transfer in the liquid water is equal to heat gained by the ice
Heat transfer by liquid water is therefore;
- DH = 6.02 kJ/mol) = 150 × 4.18 × (T1 - T2)
- 6020 J/mol = 627 × (20 - T2)
However, since 18g of water makes one mole
- 6020 J/mol = 6020/18 = 334.44 J/g.
T2 = 19.467°C
Read more on heat:
brainly.com/question/21406849
Answer:
0.005 M
Explanation:
Given data:
volume of sample solution ( volume of D ) = 5.0 mL
volume of added stock solution ( V1 ) = 5.0 mL
concentration of added stock solution ( N1 ) = 0.02 M
Total volume of concentration ( V2 )= 10 mL = ( 5.0 mL + 5.0mL)
concentration of Total volume of sample ( C2 ) = 0.01
N2 = ( N1V1 ) / V2
= ( 0.02 * 5 ) / 10 = 0.01 m
absorbance of sample solution ( A1 ) = 0.10
absorbance of additional sample solution ( A2 ) = 0.20
attached below is the remaining part of the detailed solution
The correct answer should be option C. hope this helps