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ANTONII [103]
3 years ago
9

How much heat is absorbed by 15.5 g of water when its temperature is increased from 20.0°C to 50.0°C? The specific heat of water

is 4.184 J/(g°C).,
Chemistry
2 answers:
Zigmanuir [339]3 years ago
5 0
Q = m . C . Δ T
q : Heat absorbed
m : mass of the sample
C : The specific heat of the substance.
Δ T : The change in temperature (Final T - initial T)
So: 
q = 15.5 x 4.18 x (50 - 25) = 1619.75 J 
postnew [5]3 years ago
4 0

Answer : The heat absorbed by the water is 19.4 kJ

Explanation :

Formula used :

Q=m\times c\times \Delta T

or,

Q=m\times c\times (T_2-T_1)

where,

Q = heat absorbed = ?

m = mass of water = 15.5 g

c = specific heat of water = 4.184J/g^oC

T_1 = initial temperature  = 20.0^oC

T_2 = final temperature  = 50.0^oC

Now put all the given value in the above formula, we get:

Q=15.5g\times 4.184J/g^oC\times (50.0-20.0)^oC

Q=1945.56J=1.94\times 10^3J=1.94kJ

Therefore, the heat absorbed by the water is 19.4 kJ

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Answer:

a)

Fe^{2+}⇒Fe^{3+}+e^-

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b)

Mg⇒Mg^{2+}+2e^-

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Explanation:

A)

Remember that positive number superscripts mean electrons lack and negative numbers mean electrons 'excess' (if we compare it with the neutral element). So, for the case of Fe2+ which is converted to Fe3+, we know that in Fe2+ there is a two electrons lack, while in Fe3+ there is a 3 electrons lack; it means that Fe2+ was converted to Fe3+ but releasing one electron:

Fe^{2+}⇒Fe^{3+}+e^-

The same analysis is applied to Br2; Br2 is a molecule which is said to have a zero superscript because it is an apolar covalent bond; and it is converted to Br-, which, according to what I wrote above, means that there is a one electron excess. So, Br2 must have received an electron in order to change to Br-; but Br2 can't change to Br- as simple as that because Br2 is a molecule, not an atom; it is a molecule that has two Br atoms, so, Br2 must give two Br- ions as products, but receiving one electron for each one:

Br_2+2e^-⇒2Br^-

b)

Applying the same, in Mg2+ there is a 2 electrons lack, and in Mg is not electron lack (its superscript is zero), so Mg must have released two electrons in order to change to Mg2+:

Mg⇒Mg^{2+}+2e^-

Cr3+ has a 3 electrons lack, and Cr2+ a two electrons one, so, Cr3+ must receive an electron to convert to Cr2+:

Cr^{3+}+e^-⇒Cr^{3+}

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4 years ago
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Answer:

The direction will be changed .

Explanation:

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