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mamaluj [8]
3 years ago
10

based on the article what are some of the advantages that can be given by radio frequency and microwaves​

Chemistry
1 answer:
bonufazy [111]3 years ago
6 0

Answer:

higher data rates are

Explanation:

transmitted

as the bandwidth

is more

more antenna gain is possible

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If the boiling points of two compounds differ by 60oC at atmospheric pressure, what will be the effect on the relationship by de
boyakko [2]

Answer:

It will lead to a decrease in the boiling points

Explanation:

Decreasing the pressure exerted on a compound reduces d boiling points because a high temperature is needed also to boil a compound

6 0
3 years ago
3) The total number of orbital’s in a shell with principle quantum no (n) is​
melamori03 [73]

Answer:

nine

There are nine orbitals in the n = 3 shell. There is one orbital in the 3s subshell and three orbitals in the 3p subshell. The n = 3 shell, however, also includes 3d orbitals. The five different orientations of orbitals in the 3d subshell are shown in the figure below.

Explanation:

8 0
4 years ago
Plz answer soon need answer
marishachu [46]

Answer:

rate is faster

Explanation:

the rate of reaction increases.

7 0
3 years ago
Read 2 more answers
A equilibrium is the state in which the rate of the forward reaction is _______________ the rate of the reverse reaction.
mrs_skeptik [129]
I believe the blank is (equal).
3 0
3 years ago
water has a specific heat of 4.18 j/gK and a molar heat of vaporization of 40.7 kJ. Calculate the minimum amount of heat necessa
Marrrta [24]

Answer:

To calculate the minimum amount of heat necessary to vaporize 90 g of water starting at 20 c

Explanation:

We will use heat balance equation

Q = q1+q2 = mCΔt + nL

where

m = mass of water = 90g

C = specifi heat of water =4.18J/gK

L = Latent heat of Vaporization = 40.7kJ/mol

Δt = temperature changes = 100 - 20 = 80 degree

water at 20 degrees to water at 100 degrees

then water at 100 degrees to vapor at 100 degrees

q1 = (90g)(4.18J/gK)(80K)

q1 = 30096J=30.1kJ

But

m =90 g water, gives  n = 5mol water (divide by his molar mass which is 18g)

q2=nL= (40.7kJ/mol)(5mol)

q2=203.5kJ

the minimum amount of heat necessary to vaporize 90 g of water starting at 20 c = q1+q2 =30.1+203.5=233.6kJ

5 0
3 years ago
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