<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m
velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t
acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18
</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s
acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m
Before outlier : 7.25
After outlier : 4
7.25 - 4 = 3.25
So the mean decreases by 3.25 when the outlier is removed.
I believe the answer is D.
3^2 is 9 and 4^2 is 16, and because 9/16 was the third term in the sequence, you raise both the numerator and the denominator by the number of the term minus 1.
So to find the seventh term, you raise the numerator and denominator by 7 - 1 = 6.
So the answer is 729/4096
Answer:
<u>(-7,-3)</u>
Step-by-step explanation:
step one) solve one equation for x.
y=-3x
-3x/-3=y/-3
x=(-y/3)
step two) plug in x for the other original problem.
y=x-4
y=(-y/3)-4
step three) solve for y.
y=(-y/3)-4
y+4=(-y/3)-4+4
3*(y+4)=(-y/3)*3
3y+12=-y
(3y+12)-3y=-y-3y
12/-4=-4y/-4
y=-3
step four) plug in -3 for y and solve for x.
y=x-4
-3=x+4
-3-4=x+4-4
-7=x
<em>I am in algebra two so you can trust my answer. if you need more help lmk in the comments. happy holidays and stay safe!</em>
Answer:
14/3a²
Step-by-step explanation:
-6a × 7/-9a³
(7 × 6a) / 9a³
42a / 9a³
14a / 3a³
14/3a²
