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alex41 [277]
2 years ago
15

What is the emf produced in a 1.5 meter wire moving at a speed of 6.2 meters/second perpendicular to a magnetic field of strengt

h 3.96 × 10-3 newtons/amp·meter ?
A. 37 volts
B. 0.0026 volts
C. 5.0 volts
D. 0.37 volts
E. 0.037 volts
Chemistry
1 answer:
valentinak56 [21]2 years ago
5 0

Answer:

0.037 volts

Explanation:

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<h3>Answer:</h3>

The centripetal acceleration is 26.38 m/s²

<h3>Explanation:</h3>

We are given;

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We are required to calculate the centripetal acceleration.

To get the centripetal acceleration is given by the formula;

Centripetal acc = V²/r

Where, V is the velocity and r is the radius.

Since time for 1 revolution is 1.18 seconds,

Then, V = 2πr/t, taking π to be 3.142 ( 1 revolution = 2πr)

Therefore;

Velocity = (2 × 3.142 × 0.93 m) ÷ 1.18 sec

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Thus;

Centripetal acceleration = (4.953 m/s)² ÷ 0.93 m

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Hence, the centripetal acceleration is 26.38 m/s²

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<u>Answer:</u>

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