Which type of chemical reaction occurs in 2KClO3 Right arrow. 2KCl + 3O2

A box (with two ropes attached to it) rests on a table. Bob pulls to the left with

Anton [14]

Answer:

50 N

Explanation:

it evens out at 200 N but because she's pulling with 250 her side pulls with 50 meaning it would be a pulling force of 50

6 0

4 years ago

Why are most anions basic in H2O? Give formulas of four anions that are not basic.

AVprozaik [17]

Answer:

The anions that can act as bases (conjugate bases of weak acids) have the capability to hydrolyse water and produce OH− ions. Cl−, Br−NO−3, SO2−4 are all conjugate bases of strong acids that don't have the capability to hydrolyse water and so they aren't basic.

Explanation:

5 0

3 years ago

Elena makes the table below to determine the number of atoms of each element in the chemical formula 3(NH4)2SO4

frozen [14]

Answer:

she should not have multiplied the sulfur atoms by the subscript 4

Explanation:

5 0

3 years ago

Read 2 more answers

1) the average rate of reaction in the first minute

iragen [17]

1. 0+15+30+45+60=150/5=30 s

0+10+16+22+27=75/5=15 cm^3

then, 15/30= 0.5 cm^3/s(average rate of rxn)

2. 0+15+30+45+60+75+90+105+120=540/9=60 s

0+10+16+22+27+31.50+36+39.5+42=224/9=24.89cm^3

then, 24.89/60=0.414cm^3/s (avrg rate of rxn)

3. overall rxn add all the time divide by 12 and the volume add them too and divide by 12. after take average volume divide by the average time to get the average rate of overall rxn

4. 16/30= 0.533cm^3/s

5. 39.5/105= 0.37cm^3/s

3 0

3 years ago

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is the max

jolli1 [7]

Answer: The mass of aluminium chloride that can be formed are 46.3 g

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Aluminium:

Given mass of aluminium = 32 g

Molar mass of aluminium = 26.98 g/mol

Putting values in above equation, we get:

$\text{Moles of aluminium}=\frac{32g}{26.98g/mol}=1.186mol$

For Chlorine:

Given mass of chlorine = 37 g

Molar mass of chlorine = 71 g/mol

Putting values in above equation, we get:

$\text{Moles of chlorine gas}=\frac{37g}{71g/mol}=0.521mol$

For the given chemical equation:

$2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)$

By Stoichiometry of the reaction:

3 moles of chlorine gas is reacting with 2 moles of aluminium.

So, 0.521 moles of chlorine gas will react with = $\frac{2}{3}\times 0.521=0.347moles$ of aluminium.

As, given amount of aluminium is more than the required amount. Thus, it is considered as an excess reagent.

So, chlorine gas is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

3 moles of chlorine gas is producing 2 moles of aluminium chloride

So, 0.521 moles of chlorine gas will react with = $\frac{2}{3}\times 0.521=0.347moles$ of aluminium chloride.

Now, calculating the mass of aluminium chloride by using equation 1, we get:

Moles of aluminium chloride = 0.347 moles

Molar mass of aluminium chloride = 133.34 g/mol

Putting all the values in equation 1, we get:

$0.347mol=\frac{\text{Mass of aluminium chloride}}{133.34g/mol}\\\\\text{Mass of aluminium chloride}=46.3g$

Hence, the mass of aluminium chloride that can be formed are 46.3 g

7 0

4 years ago