Answer:
Death Valley California
C(t) = -0.30 (0)² + 40
C(t) = 40
C(t) = -0.30 (12)² + 40t – 12)2 + 40
65f
Answer:
A' = 2,-2
B' = 2,-4
C' = 5,-4
Step-by-step explanation:
Answer:
p(t) = 100%·2^(-t/1.32)
Step-by-step explanation:
The equation for exponential decay is ...
(remaining amount) = (initial amount)·2^(-t/(half-life))
Here, we can represent the percentage remaining by p(t) and the initial amount by 100%. Then, for a half-life of 1.32 minutes, the amount remaining is ...
p(t) = 100%·2^(-t/1.32) . . . . . where t is in minutes
_____
Alternate functional forms are possible, such as ...
p(t) = 100%·e^(-0.525112t)
p(t) = 100%·0.591489^t
Answer:
the Largest shed dimension is 13.5 ft by 13.5 ft
Largest Area is 182.25 ft²
Step-by-step explanation:
Given that;
Perimeter = 54 ft
P = 2( L + B ) = 54ft
L + B = 54/2
L + B = 27 ft
B = 27 - L ------------Let this be equation 1
Area A = L × B
from equ 1, B = 27 - L
Area A = L × ( 27 - L)
A = 27L - L²
for Maxima or Minima
dA/dL = 0
27 - 2L = 0
27 = 2L
L = 13.5 ft
Now, d²A/dL² = -2 < 0
That is, area is maximum at L = 13.5 using second derivative test
B = 27 - L
we substitute vale of L
B = 27 - 13.5 = 13.5 ft
Therefore the Largest shed dimension = 13.5 ft by 13.5 ft
Largest Area = 13.5 × 13.5 = 182.25 ft²
When x is 0 y would be -7 and when x=-1 y=-16
