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Sindrei [870]
3 years ago
8

A system of linear equations has infinitely many solutions based on inspection. What indicated that the system has infinitely ma

ny solutions?
Mathematics
2 answers:
taurus [48]3 years ago
7 0
The lines are on top of each other and don’t have one specific point where they meet. That’s what I would put
7nadin3 [17]3 years ago
3 0
Same slope and same y- intercept
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Four sizes of scaled text are shown.
shusha [124]

Answer:

Hello!

Okay, so how I solved this answer was I actually of went backwards in order. What I mean by that is I found the scale of \frac{1.954}{1.563}. Put this division equation into a calculator and then multiply the quotient by 1.0. This should give you an answer of approximately 1.250. 1.250 is the unknown text size for this problem. I took a quiz with this exact same problem and got the answer correct, so I can verify that this is an accurate answer. I hope this helps. Have a lovely day! :)

Step-by-step explanation:

4 0
3 years ago
Find the slope and the y-intercept of the line.<br> 6x+2y=-2
chubhunter [2.5K]

Answer:

Slope: -3

Y Intercept: (0,-1)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Answer this question please!
k0ka [10]

Answer:

Step-by-step explanation:

5 0
3 years ago
What o divided 0 plus 4
amm1812
0 divided by 0= 0 plus 4= 4
answers 4
7 0
4 years ago
Read 2 more answers
X = 10<br><br> x = 2<br><br> x = two divided by five.<br><br> x = 11
KengaRu [80]

Answer:

x = 10

Step-by-step explanation:

You can try the answers to see which works. (The first one does.)

Or, you can solve for the variable:

Divide by 75

... (1/5)^(x/5) = 3/75 = 1/25

Recognize that 25 = 5^2, so ...

... (1/5)^(x/5) = (1/5)^2

Equating exponents, you have

... x/5 = 2

... x = 10 . . . . . multiply by 5

_____

You can also start by taking logarithms:

... log(75) +(x/5)log(1/5) = log(3)

... (x/5)log(1/5) = log(3) -log(75) = log(3/75) = log(1/25) . . . . simplify the log

... x/5 = log(1/25)/log(1/5) = 2 . . . . . simplify (or evaluate) the log expression

... x = 10 . . . . . multiply by 5

_____

"Equating exponents" is essentially the same as taking logarithms.

5 0
3 years ago
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