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3 years ago

8

A system of linear equations has infinitely many solutions based on inspection. What indicated that the system has infinitely ma

ny solutions?

2 answers:

taurus [48]3 years ago

7 0

The lines are on top of each other and don’t have one specific point where they meet. That’s what I would put

7nadin3 [17]3 years ago

3 0

Same slope and same y- intercept

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If sin theta =3/7 and tan theta <0 what is the value of cos theta

Savatey [412]

Remember that

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

So if $\sin\theta>0$ and $\tan\theta$ , then we know $\cos\theta$ .

Then use the Pythagorean identity to solve for cosine:

$\cos^2\theta+\sin^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac{2\sqrt{10}}7$

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3 years ago

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2 years ago

2x + 6 = 20<br> Please answer quickly options for x are 6,7,5,8 they are one of those numbers

BaLLatris [955]

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Step-by-step explanation:

Or, you don't have to plug any of those in and solve for x

subtract 6 from both sides

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3 years ago

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3 years ago

A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.

Papessa [141]

<u>Answer:</u>

$\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}$

<u>Step-by-step explanation:</u>

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

$\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}$

$\bf \implies n_{cubes} = \dfrac{20cm \times 6cm \times 4cm .}{2cm \times 2cm \times 2cm } \\\\\bf\implies n_{cubes} = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }$

<h3><u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>

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3 years ago