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11111nata11111 [884]
2 years ago
11

How to solve? Would you divide by 4? 4 representing the four corners

Mathematics
1 answer:
charle [14.2K]2 years ago
3 0

Answer:

paper left = 168.56 units²

Step-by-step explanation:

first, figure the area of the square:

area of square = 28x28 = 784 units²

second, figure the area of the circle:

radius = 1/2of 28 = 14

area of circle = Pi x Radius² = (3.14)(14)² = 615.44 units²

subtract area of circle from area of square:

784 - 615.44 = 168.56 units²

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The area of a square is 121 square feet. What is the perimeter of the square
Ugo [173]

Answer:

44 feet

Step-by-step explanation:

square root of 121 is 11

so each side of the square is 11

11 x 4 = 44

6 0
3 years ago
Solve the system by substitution 3x+y=-16 and y=-x-4
kap26 [50]

Solution,

y = -x-4......(i)

3x + y =- 16.......(ii)

Now,

Substituting the value of y in equation (ii)

or, 3x + (-x-4)= -16

or,3x - x - 4 = -16

or, 2x= -16 +4

or, x = -12/2

: x = -6

Then,

Substituting the value of x in (i) equation;

or,y= -(-6) - 4

or,y= 6 - 4

: y =2

7 0
3 years ago
Simplify x^2-9x+14/x^2+5x-14
Kryger [21]
X-7 over x+7 i think
7 0
2 years ago
5. Sara has a photo that is 5 inches by 7 inches. When she adds a frame
stiv31 [10]

Answer:

  1 inch

Step-by-step explanation:

Factors of 63 are 7 and 9, each of which is 2 more than the dimensions of the photo. Sarah's frame is 1 inch wide.

_____

A 1-inch wide frame adds 2 inches to length and width.

_____

<em>Solution using an equation</em>

If you let w represent the width of the frame, the area of the framed photo is ...

  (5+2w)(7+2w) = 63

  4w^2 +24w -28 = 0 . . . . write in standard form

  w^2 +6w -7 = 0 . . . . . . . . divide by 4

  (w -1)(w +7) = 0 . . . . . . . . factor

The positive solution to this equation is w=1.

The width of the frame is 1 inch.

5 0
3 years ago
Find the slope of the line that passes through (10,4) and (7,9)
Mkey [24]

I will take you the steps to obtain the slopes passing two points

step 1 : list the parameters

\begin{gathered} \text{from (10, 4)} \\ x_1=10,y_1=\text{ 4} \\ \text{from (7,9)} \\ x_2_{}=7,y_2=\text{ 9} \end{gathered}

step 2: Apply the equation to obtain the slope between two points

\begin{gathered} \text{slope = }\frac{rise}{fall}=\frac{y_2-y_1}{x_2-x_1} \\  \\ \Rightarrow\frac{9\text{ - 4}}{7\text{ - 10}}\text{ =}\frac{5}{-3} \\  \\ slope=-\frac{5}{3} \end{gathered}

4 0
1 year ago
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