The first 4 terms are 6,7,8,9 and the 10th term is 15 for given sequence.
Given:
n + 5
substitute n = 1,2,3,4....
= n+5
= 1+5
= 6
= 2+5
= 7
= 3+5
= 8
= 4+5
= 9
First four terms are 6,7,8,9
a + (n-1)d
= 6 + (10-1)1
= 6+9*1
= 15
10th term = 15
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Full question:
For each sequence find the first 4 terms and the 10th term:
n + 5.
Answer:
C or 9, 40, 41
Step-by-step explanation:
Step-by-step explanation:
let debbie be x years
let felix be 6x years
in 12 years felix will be 2x older than debbie
do the calc
I disagree with her she will spent more than that because 6×5.29=31.74$ for 6 roses+4×3.59=14.36 4carnations +8×4.79=38.32$for 4 tulips and then 31.74+14.36+38.32=84.42$ all together
Answer: which is the same as
If the math notation does not load properly, or the font size is too small, then it says ( (x+4)(x-1) )/( (x+4)(x+2) ) which is the same as (x^2+3x-4)/(x^2+6x+8)
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Explanation:
We see that x cannot equal -2, as this prevents the denominator (x+2) from becoming zero. If x = -4, then x+4 = 0. So x not allowed to be -4 means (x+4) is prevented in being zero, and this is the missing factor in the denominator. We can never divide by zero.
Multiply top and bottom of this given fraction by (x+4) to get
Note how the (x+4) terms divide and cancel to get back to the original fraction given. The portion sticks around to make sure the domains line up properly.
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Optionally you can expand out each product in the numerator and denominator to get
(x+4)(x-1) = x^2-x+4x-4 = x^2+3x-4
(x+4)(x+2) = x^2+2x+4x+8 = x^2+6x+8
I used the FOIL rule
So,