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2 years ago

15

PLEASE HELP NO BOTS!

1 answer:

Semenov [28]2 years ago

7 0

Answer:

3. DC ≅ CA

4. Vertical Angles Theorem

6. CPCTC

Step-by-step explanation:

I hope this helps :)

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Gertie ran 3/4 mile during physical education class. Sarah ran 2/4 mile during the same class. How much farther did Gertie run t

Marizza181 [45]

Gertie 3/4 mile.

Sarah 2/4 mile.

Gertie ran farther by: 3/4 - 2/4 = (3 -2)/4 = 1/4

Gertie ran farther by 1/4 mile.

6 0

3 years ago

Read 2 more answers

Find the function values

babymother [125]

Step-by-step explanation:

f(x)=3x−2 so when the variable x is replace with an actual value ( − 1 ) we get f(−1)=3(−1)−2

=−3−2

=−5

4 0

1 year ago

A population of insects increases at a rate of 1.5% per day. About how long will it take the population to double?

Debora [2.8K]

Answer:

66.67 days

Step-by-step explanation:

8 0

3 years ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

5 0

3 years ago

What is the slope of the line passing through (3, 7) and (-2, -3)

givi [52]

Answer:

the slope of the given line = 2

Step-by-step explanation:

here's the solution :-

=》

$slope = \frac{y2 - y1}{x2 - x1}$

=》

$\frac{7 - ( - 3)}{3 - ( - 2)}$

=》

$\frac{7 + 3}{3 + 2}$

=》

$\frac{10}{5}$

=》

$2$

6 0

3 years ago