Answer:
atomic mass of X is 48.0 amu
Explanation:
Let y be the atomic mass of X
Molar mass of O_2 is = 2×16 = 32 g / mol
X + O2 -----> XO_2
According to the equation ,
y g of X reacts with 32 g of O_2
24 g of X reacts with Z g of O_2
Z = ( 32×24) / y
But given that 24.0 g of X exactly reacts with 16.0 g of O_2
So Z = 16.0
⇒ (32×24) / y = 16.0
⇒ y = (32×24) / 16
y= 48.0
So atomic mass of X is 48.0 amu
The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
<h3>What is current?</h3>
The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:

There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:

The mass of Ni to be deposited is 1.22 grams. The charge required is given as:

The current required to transfer 4010.7 C of charge in 1800 seconds is given as:

Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
Learn more about current, here:
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It forms Carbon monoxide.
CO2 +O2⇒ CO
(Sorry not balanced)
Answer: the concentration of [CO]= 0.0532M
Explanation:
From The equation of reaction
2H2(g) + CO(g) ⇌ CH3OH(g)
Applying Kc= [CH3OH]/[H2]^2[[CO]
[CH3OH]= 0.00487
[CO]= x-0.00487
[H2]=(0.032-0.00487)^2=0.0271
Substitute into formula
Kc=[CH3OH]/[H2]^2[[CO]
35= 0.00487/(0.0271)^2(x-0.00487)
Simplify
x-0.00487=0.189
x= 0.00487+0.189=0.193moles
[CO]= n/C= 0.193/3.63= 0.0532M
Answer:

Explanation:
because it is products / reactants
Hope this helps:)