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Finger [1]
3 years ago
13

How many joules of heat energy are released when 50.0 g of water are cooled from 70.00C to 60.00C?

Chemistry
1 answer:
baherus [9]3 years ago
5 0

Answer:

2090 joules are released.

Explanation:

Calorimetry is applied to this problem:

Q = m . C . (Final T° - Initial T°)

C is the Specific Heat, a constant for each substance, that determines the heat per unit mass, which is required to raise one degree Celsius.

C for water is 4.18 kJ /kg.°C

We convert the mass of water to kg

50 g . 1kg / 1000 g = 0.05 kg

Let's replace data in the formula:

Q = 0.05 kg . 4.18 kJ /kg.°C (60°C - 70°c)

Q = -2.09 kJ

As we have a negative value, heat is released. We need the |Q| for the value

2.09 kJ . 1000 J /kJ = 2090 joules

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a culinary student fills a 40ml container with 37.2 grams of vegetable oil.What is the density of the oil
Lynna [10]

Answer:

<h2>0.93 g/mL</h2>

Explanation:

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density =  \frac{mass}{volume} \\

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density =  \frac{37.2}{40}  \\  = 0.93

We have the final answer as

<h3>0.93 g/mL</h3>

Hope this helps you

4 0
3 years ago
Convert the following numbers of calories or
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a 32823.48joules

b  1979.8688 joules

c. 1979.8688

Explanation:

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Sleet falls from clouds as ice particles.<br> True<br> O<br> False
shtirl [24]

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Explanation:

3 0
3 years ago
Read 2 more answers
We have an aqueous solution that contains 29% (by mass) of a hypothetical solute Z. The formula weight of the solute Z is 242 g/
malfutka [58]

Answer:

The molarity of Z in this solution is 1.80 mol/L

Explanation:

29% (by mass) means that in 100 g of solution, you have 29 grams of solute.

So, by the solution density we can find our volume.

Density = mass / volume

Solution density = mass solution / volume solution

1.5 g/ml = 100 g / volume solution

volume solution = 100 g/ 1..5 g/ml

volume solution = 66.6 mL

So we have just found out that in 66.6 mL, we have 29 g of solute Z, so if we want to know the molarity, we have to find out the mass in 1 L, and afterwards, calculate the moles, we have

1000 mL = 1L

66.6 mL ____ 29 g of solute Z

1000 mL ____ (29 g . 1000 mL)/ 66.6 mL = 435.4 g

With the molar mass (formula weight), we can find out the moles

Mass /Molar mass = Mol

435.4 g /242 g/m = 1.80 mol

Molarity is 1.80 mol/L

4 0
3 years ago
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