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3 years ago

1. What is the mass of 105.00 moles of H20?

2 answers:

5 0

The average mass of one H2O molecule is 18.02 amu. The number of atoms is an exact number, the number of mole is an exact number; they do not affect the number of significant figures. The average mass of one mole of H2O is 18.02 grams. This is stated: the molar mass of water is 18.02 g/mol.

Explanation:

alexandr1967 [171]3 years ago

3 0

Answer:

1891.575 g.

Explanation:

The molar mass of water = 2 * 1.008 + 15.999 = 18.015 g.

So 105 moles = 1891.575 g.

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Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an

garri49 [273]

Explanation:

The given data is as follows.

T = $120^{o}C$ = (120 + 273.15)K = 393.15 K,

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So, $x_{1}$ = 0.5 and $x_{2}$ = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

$p^{sat}_{1}$ (393.15 K) = 9.2 bar

$p^{sat}_{1}$ (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

$p_{1} = x_{1} \times p^{sat}_{1}$

= $0.5 \times 9.2 bar$

= 4.6 bar

and, $p_{2} = x_{2} \times p^{sat}_{2}$

= $0.5 \times 10.5 bar$

= 5.25 bar

Therefore, the bubble pressure will be as follows.

P = $p_{1} + p_{2}$

= 4.6 bar + 5.25 bar

= 9.85 bar

Now, we will calculate the vapor composition as follows.

$y_{1} = \frac{p_{1}}{p}$

= $\frac{4.6}{9.85}$

= 0.467

and, $y_{2} = \frac{p_{2}}{p}$

= $\frac{5.25}{9.85}$

= 0.527

Calculate the dew point as follows.

$y_{1}$ = 0.5, $y_{2}$ = 0.5

$\frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}$

$\frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}$

$\frac{1}{P}$ = 0.101966 $bar^{-1}$

P = 9.807

Composition of the liquid phase is $x_{i}$ and its formula is as follows.

$x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}$

= $\frac{0.5 \times 9.807}{9.2}$

= 0.5329

$x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}$

= $\frac{0.5 \times 9.807}{10.5}$

= 0.467

4 0

3 years ago

You need to determine the specific gravity of a sample. After putting the sample on a lab scale, you know it has a mass of 85 gr

BlackZzzverrR [31]

Answer:

Specific gravity of the sample = 8.947

Explanation:

Specific gravity of a substance is defined as the density of that substance divided by the density of water.

Density of water = 1000g/l

Density of substance = mass/volume

= 85/9.5 x 10^-3

= 8947.37 g/l

SG = 8947.37/1000

= 8.947

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2 years ago

Using the phase diagram for CO2, what phase is carbon dioxide in at -20°C

djyliett [7]

Answer:

A. It is in the gas phase.

Explanation:

it was correct on ap3x :)

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What is a feed back loop?

Agata [3.3K]

Answer:A feedback loop is a process in which the outputs of a system are circled back and used as inputs. In business, this refers to the process of using customer or employee feedback (the outputs of a service or product), to create a better product or workplace

Explanation: Becuz ur mom

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3 years ago

A plasma that has particles that never collide frequently enough to exchange kinetic energy and never reach a temperature equal

Colt1911 [192]

Answer: Thermal plasma

Explanation:

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2 years ago

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