Answer:
x = 10
Step-by-step explanation:
Let's draw the center of the circle S and the segments SE and SD.
SE is perpendicular to EF (as EF is tangent to circle).
That means FED + DES = 90deg
We also know that DSE = 120deg
And because the SED is an isosceles triangle, we know that angle measures for DES and SDE are equal.
DES = (180deg - 120deg) / 2 = 30deg
FED = 90deg - DES = 90deg - 30deg = 60deg
7x - 10 = 60
7x = 70
x = 10
See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16