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Irina18 [472]
3 years ago
15

Differences between adhesion and cohesion​

Physics
2 answers:
pickupchik [31]3 years ago
7 0

Answer:

As for the definitions, the tendency of two or more different molecules to bond with each other is known as Adhesion, whereas the force of attraction between the same molecules is known as Cohesion.

hopefully this helps

pav-90 [236]3 years ago
6 0

Answer:

Adhesion is the force of attraction between molecules of different substances while cohesion is the force of attraction between molecules of same substances.

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A 2.7-cm-tall object is 20 cm to the left of a lens with a focal length of 10 cm . A second lens with a focal length of 48 cm is
irina1246 [14]

Answer

given,

height of object = 2.7 cm

distance left of lens (u₁)= 20 cm

focal length of lens(f₁)= 10 cm  

the distance of image

\dfrac{1}{f_1}=\dfrac{1}{u_1}+\dfrac{1}{v_1}

\dfrac{1}{v_1}=\dfrac{1}{f_1}-\dfrac{1}{u_1}

\dfrac{1}{v_1}=\dfrac{1}{10}-\dfrac{1}{20}

   v₁ = 20 cm

magnification of first lens

m_1= -\dfrac{v}{u}

m_1=-\dfrac{20}{20}

    m₁ = -1

distance of object from the second lens

   u₂ = 52-20 = 32 cm

   f₂ = 48 cm

now,

\dfrac{1}{f_2}=\dfrac{1}{u_2}+\dfrac{1}{v_2}

\dfrac{1}{v_2}=\dfrac{1}{f_2}-\dfrac{1}{u_2}

\dfrac{1}{v_2}=\dfrac{1}{48}-\dfrac{1}{52}

   v₁ = 624 cm

magnification of first lens

m_1= -\dfrac{v}{u}

m_1=-\dfrac{624}{52}

    m₁ = -12

total magnification

m = m₁ m₂

m = (-1)(-12)

m = 12

height of image

m =-\dfrac{h'}{h}

12=-\dfrac{h'}{2.7}

h' = -32.4 cm

a) distance between image and second lens is equal to 624 cm

b) height of image is equal to 32.4 cm

       

4 0
3 years ago
Barnard's star is a near neighbor of the Sun whose properties we know quite well. It is a type M4V with absolute magnitude 13.22
vitfil [10]

Answer:

The star is at a distance of 100 parsecs.

Explanation:

The distance can be determined by means of the distance modulus:

M - m = 5log(d) - 5  (1)

Where M is the absolute magnitude, m is the apparent magnitude and d is the distance in units of parsec.

Therefore, d can be isolated from equation 1

log(d) = (M - m + 5)/5

Then, Applying logarithmic properties it is gotten:

d = 10^{(M - m + 5)/5}  (2)

The absolute magnitude is the intrinsic brightness of a star, while the apparent magnitude is the apparent brightness that a star will appear to have as is seen from the Earth.

Since both have the same spectral type is absolute magnitude will be the same.

Finally, equation 2 can be used:

d = 10^{(13.22 - 8.22+ 5)/5}  

d = 100 pc    

Hence, the star is at a distance of 100 parsecs.

Key term:

Parsec: Parallax of arc seconds

8 0
3 years ago
Earth orbits once around the Sun about every 365 days. The Moon orbits around Earth. About how many days does it take the Moon t
PtichkaEL [24]
The answer is is 730.5 days rounded, so A. 730
3 0
3 years ago
Suppose you charges parallel plate capacitor with a dielectric between the plates using a battery and the. Remove the bater, iso
Makovka662 [10]

Answer:

A) increase.

Explanation:

  • By definition, the capacitance of a capacitor, is the charge on one of the plates, divided by the potential difference between them, as follows:

        C = \frac{Q}{V} (1)

  • At the same time, we can show (applying Gauss' Law to the surface of one of the plates), that the capacitance of a parallel-plate capacitor (with a dielectric of air), can be written as follows:

       C = ε₀*A / d  (2)

  • If the space between plates, is filled with a dielectric of dielectric constant κ, the above equation becomes:

       C =\frac{\epsilon_{0}*\kappa*A}{d} (3)

  • If the capacitor, once charged, is disconnected from the battery, charge must keep the same.
  • Now, if we remove the dielectric, as stated in (3) and (2), the capacitance C will decrease when removing the dielectric.
  • From (1) if C decreases, and Q remains constant, in order to keep both sides of the equation equal each other, V (the potential difference between plates), must increase.    
7 0
3 years ago
A rectangular tank is filled with water to a depth of 4m. Calculate the pressure at the bottom of the tank. PLEASEEE HELP!!
Paul [167]

The pressure in a liquid at a given depth is called the hydrostatic pressure. This can be calculated using the hydrostatic equation:

P = ρgh

P = (1000 kg/m³)(9.8 m/s²)(4 m)

<h2>P = 39200 Pa</h2>

4 0
3 years ago
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