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tester [92]
4 years ago
5

A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its speed is 4 m/s. But 3 sec

onds later, at the bottom of the slope, its speed is 22 m/s. What is its average acceleration?
Physics
1 answer:
NikAS [45]4 years ago
8 0

Answer:

67676

Explanation:

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A 200 kg roller coaster is located at the top of a hill where the height is 30 m. What is the velocity when it reches the bottom
maw [93]

Assuming it starts at rest, the roller coaster only has potential energy at the top of the hill, which is

E_P=(200\,\mathrm{kg})(30\,\mathrm m)g

When it reaches the bottom, its potential energy will have converted to kinetic energy,

E_K=\dfrac12(200\,\mathrm{kg})v^2

where v is its velocity at that point. By the law of conservation of energy, assuming no loss of energy due to other sources (e.g. sound, heat), we have

E_P=E_K\iff(6000\,\mathrm{kg}\cdot\mathrm m)g=(100\,\mathrm kg})v^2

\implies v=\sqrt{60g}\,\dfrac{\rm m}{\rm s}\approx24.2\,\dfrac{\rm m}{\rm s}

8 0
4 years ago
Read 2 more answers
A student solving a physics problem for the range of a projectile has obtained the expression
Alika [10]

Answer:

The range of the projectile is 66.7 meters.

Explanation:

The range of a projectile is given by the following expression as :

R=\dfrac{v_o^2\ sin2\theta}{g}..............(1)

v_o=37.2\ m/s

\theta=14.1^{\circ}

g=9.8\ m/s^2

The range can be calculated using equation (1). Putting the values of all parameters we get :

R=\dfrac{(37.2)^2\ sin2(14.1)}{9.8}

R = 66.7 meters

So, the range of the projectile is 66.7 meters. Hence, this is the required solution.

6 0
3 years ago
Which has a greater buoyant force on it, a 25.0 cm3 piece of wood floating with part of its volume above water or a 25.0 cm3 pie
kozerog [31]

Answer:

piece of submerged iron

Explanation:

The buoyant force is given by:

B=\rho_L V_{sub} g

where

\rho_L is the density of the liquid (in this case, water)

V_{sub} is the submerged part of the object

g is the acceleration due to gravity

In this problem, the liquid used in the two examples is the same, water, so \rho_L is the same; and g is the same as well. Therefore, the only difference between the two examples is V_{sub}.

For the piece of wood, we are told that the object is floating, so only a fraction of its total volume of 25.0 cm3 will be submerged: therefore the submerged volume will be less than 25.0 cm3. On the contrary, the problem tells us that the piece of iron is submerged, so the submerged volume in this case is 25.0 cm3. Therefore, the submerged volume for the iron is greater than for the piece of wood, so the buoyant force of the piece of iron is greater.

8 0
3 years ago
A passenger train left station A at 6:00 p.m. Moving with the average speed 45 mph, it arrived at station B at 10:00 p.m. A tran
marishachu [46]
<h2>Average speed of transit train is 60 mph</h2>

Explanation:

Average speed of passenger train = 45 mph

Time taken from station A to station B for passenger train  = 10:00 - 6:00 = 4 hours

Distance between station A to station B = 45 x 4 = 180 miles.

Time taken from station A to station B for transit train  =  4 - 1 = 3 hours

Distance between station A to station B = Average speed of transit train x Time taken from station A to station B for transit train

180 = Average speed of transit train x 3

Average speed of transit train = 60 mph

Average speed of transit train is 60 mph

8 0
4 years ago
Can I get any help?
Pavel [41]
Try B, it seems correct. I’m very sorry if i’m incorrect.
7 0
3 years ago
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