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4 years ago

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A roller coaster car rapidly picks up speed as it rolls down a slope. As it starts down the slope, its speed is 4 m/s. But 3 sec

onds later, at the bottom of the slope, its speed is 22 m/s. What is its average acceleration?

1 answer:

NikAS [45]4 years ago

8 0

Answer:

67676

Explanation:

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The distance covered by a car at a time, t is given by x = 20t + 6t4, calculate

Anni [7]

Answer:

(i) v = 44 m/s

(ii) a = 72 m/s^2

Explanation:

You have the following equation for the potion of a car:

$x=20t+6t^4$

(i) The instantaneous velocity is the derivative of x in time:

$\frac{dx}{dt}=20+(6)(4)t^3=20+24t^3$

for t = 1 is:

$v(t=1)=\frac{dx}{dt}=20+24(1)^3=44m/s$

(ii) The instantaneous acceleration is the derivative of the velocity:

$\frac{dv}{dt}=24(3)t^2=72t^2$

for t = 1

$a(t=1)=\frac{dv}{dt}=72(1)^2=72m/s^2$

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Sladkaya [172]

Answer:

B. develop hypotheses that will be subjected to empirical test.

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amm1812

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